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3 years ago

What are the roots of x in - 10x2 + 12x - 9 = 0?

Mathematics

2 answers:

Leya [2.2K]3 years ago

8 0

Answer:

Thus, The two roots of the given quadratic equation are : x = 0.5225 or x = -1.7225

Step-by-step explanation:

The quadratic equation is given to be :

10x² + 12x - 9 = 0

A = 10 , B = 12 , C = 9

Now, using the discriminant rule :

$x=\frac{-B\pm\sqrt{B^2-4AC}}{2A}\\\\\implies x=\frac{-12\pm\sqrt{144+360}}{20}\\\\ \implies x =\frac{-12\pm 22.45}{20}$

So, x = 0.5225 or x = -1.7225

Thus, The two roots of the given quadratic equation are : x = 0.5225 or x = -1.7225

ivann1987 [24]3 years ago

3 0

SORRY FOR CUTTING AND HANDWRITING

HOPE THIS WILL HELP YOU

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A company maintains a large fleet of automobiles. To check the average number of miles driven per month, a random sample of 100

Bas_tet [7]

Answer:

$df=n-1=100-1=99$

Since is a two sided test the p value would be:

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Step-by-step explanation:

Data given

$\bar X=2690$ represent the sample mean

$s=360$ represent the sample standard deviation

$n=100$ sample size

$\mu_o =2600$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean of interest is different from 2600, the system of hypothesis would be:

Null hypothesis: $\mu = 2600$

Alternative hypothesis: $\mu \neq 2600$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Calculate the statistic

The statistic for this case is given $t_{calc}=2.7$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=100-1=99$

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3 years ago

Given circle O, angle A has a measure of 36° and the radius is 10 cm, find the area of sector BOC.

Fed [463]

Answer:

The area of the sector BOC is A' = 31.4 $cm^{2}$

Step-by-step explanation:

Radius of the circle = 10 cm = 0.1 m

Angle of sector $\theta$ = 36°

Area of the circle A = $\pi r^{2}$

A = 3.14 × $0.1^{2}$ = 0.0314 $m^{2}$

Now area of the sector BOC is

$A' = A (\frac{\theta}{360} )$

$A' = 0.0314 (\frac{36}{360} )$

A' = 0.00314 $m^{2}$ = 31.4 $cm^{2}$

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4 years ago

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gregori [183]

Answer:

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Step-by-step explanation:

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3 years ago

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Graph the line with slope-2/3 passing through the point (-5, -4),

Orlov [11]

Answer:

The figure is attached down

Step-by-step explanation:

To graph a line you must have its equation

The form of the linear equation is y = m x + b, where

m is its slope
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∵ The slope of the line is $-\frac{2}{3}$

∴ y = $-\frac{2}{3}$ x + b

- To find b substitute x and y in the equation by the coordinates

of a point on the line

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∴ x = -5 and y = -4

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∴ $-\frac{22}{3}$ = b

∴ y = $-\frac{2}{3}$ x - $\frac{22}{3}$

To draw the line substitute x by any two values and find their ys

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∴ y = $-\frac{2}{3}$ (-2) - $\frac{22}{3}$

∴ y = -6

∴ The line passing through point (-2 , -6)

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∴ y = -8

∴ The line passing through point (1 , -8)

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∴ y = $-\frac{2}{3}$ (4) - $\frac{22}{3}$

∴ y = -10

∴ The line passing through point (4 , -10)

Now we can make a table to draw the line

→ x : -5 : -2 : 1 : 4

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Look to the attached graph

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4 years ago

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stellarik [79]

Answer:

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Step-by-step explanation:

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4 years ago

What are the roots of x in - 10x2 + 12x - 9 = 0?​

What are the roots of x in - 10x2 + 12x - 9 = 0?