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shepuryov [24]
3 years ago
13

Enzymes catalyze reaction by stabilizing the _________. If the enzyme binds to the substrate too well, the activation energy for

the catalyzed reaction _________. Thus, the enzyme binds best to the _________, and the activation energy _________.
Chemistry
2 answers:
Maksim231197 [3]3 years ago
7 0

Answer:

Transition state, decreases, substrates & gets decreased.

Explanation:

Most of the chemical reactions are slow because of the transition state barriers. It requires a lot of energy to cross the transition state barriers. So enzymes provide an alternate pathway for carrying out the reaction by stabilizing the transition state. When enzymes interact with the substrates with the help of functional groups present in their active sites it results in the lowering of activation energy because the transition state gets stabilized with the help of enzyme.

Soloha48 [4]3 years ago
5 0

by photosynthesis make it enzymes

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Please help me! Will mark brainliest! Thank you!
Kamila [148]

Answer:

gas

Explanation:

8 0
3 years ago
Which of the following is an example of a molecule?
xxMikexx [17]
O2 is an example of a molecule
5 0
3 years ago
An object has a mass of 6.8 g and volume of 34 mL. What is the density of the object?​
jenyasd209 [6]

Answer:

<h2>Density = 0.2 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

<h3>Density =  \frac{mass}{volume}</h3>

From the question the points are

mass = 6.8 g

volume = 34 mL

Substitute the values into the above formula and solve

That's

<h3>Density =  \frac{6.8}{34}</h3>

We have the final answer as

<h3>Density = 0.2 g/mL</h3>

Hope this helps you

7 0
3 years ago
Match these items.
notka56 [123]
Litmus is an indicator
Charged particles are ions
Acids contain H+ ions
Bases contain OH - ions
Hydronium ions are H3O+

Now, I have to take issue with the last one
A base of pH 14 is not a strong base, it would be a highly concentrated base. A strong base is a base that completely deionizes in water.

But technically, for the purpose of your answer strong base = pH 14
6 0
3 years ago
What is the Ka of a weak acid (HA) if the initial concentration of weak acid is 4.5 x 10-4 M and the pH is 6.87? (pick one)
rewona [7]

Answer:

Ka = 4.04 \times 10^{-11}

Explanation:

Initial concentration of weak acid = 4.5 \times 10^{-4}\ M

pH = 6.87

pH = -log[H^+]

[H^+]=10^{-pH}

[H^+]=10^{-6.87}=1.35 \times 10^{-7}\ M

HA dissociated as:

HA \leftrightharpoons H^+ + A^{-}

(0.00045 - x)    x     x

[HA] at equilibrium = (0.00045 - x) M

x = 1.35 \times 10^{-7}\ M

Ka = \frac{[H^+][A^{-}]}{[HA]}

Ka = \frac{(1.35 \times 10^{-7})^2}{0.00045 - 0.000000135}

0.000000135 <<< 0.00045

Therefore, Ka = \frac{(1.35 \times 10^{-7})^2}{0.00045 } = 4.04 \times 10^{-11}

5 0
3 years ago
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