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kvv77 [185]
3 years ago
10

(a) Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 7.0 g. Silver has 47 electr

ons per atom, and its molar mass is 107.87 g/mol.
Chemistry
1 answer:
RideAnS [48]3 years ago
7 0

<u>Answer:</u> The number of electrons in given amount of silver are 1.839\times 10^{24}

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

......(1)

We are given:

Mass of silver = 7.0 g

Molar mass of silver = 107.87 g/mol

Putting values in equation 1:

\text{Moles of silver}=\frac{7.0g}{107.87g/mol}=0.0650 mol

According to the mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of particles.

Number of electrons per atom of silver = 47

So, 0.065 moles of silver will contain = (0.065\times 6.022\times 10^{23}\times 47)=1.839\times 10^{24} number of electrons

Hence, the number of electrons in given amount of silver are 1.839\times 10^{24}

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