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Alex
4 years ago
10

The perimeter of a rectangle is 59

Mathematics
1 answer:
Lelu [443]4 years ago
5 0
Perimeter = 2(length + width)
59 = 2(14+x)
59 = 28 + 2x
31 = 2x
15.5 = x

Width = 15.5
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Find area of a parallelogram with a height of 8 inches and a base of 14 inches
12345 [234]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{112 \:  {inches} \: ^{2} }}}}}

Step-by-step explanation:

Given,

Height of a parallelogram ( h ) = 8 inches

Base of a parallelogram ( b ) = 14 inches

Area of a parallelogram ( A ) = ?

<u>Finding </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>parallelogram</u>

<u>\boxed{ \sf{area \: of \: parallelogram \:  =  \: base \:  \times  \: height}}</u>

⇒<u>\sf{area \: of \: parallelogram \:  =  \: 14  \: \times 8}</u>

⇒<u>\sf{area \: of \: parallelogram = 112 \:  {inches}^{2} }</u>

Hope I helped!

Best regards! :D

4 0
4 years ago
Find the right quotient. 36m 5 n 5 ÷ (12m 3)
polet [3.4K]
ANSWER

The right quotient is

3  {m}^{2} {n}^{5}

EXPLANATION


The given expression is :

\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }



\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  \frac{36}{12}  \times  \frac{ {m}^{5} }{ {m}^{3}} \times  {n}^{5}


\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  3\times  \frac{ {m}^{5} }{ {m}^{3}} \times  {n}^{5}


Recall that,


\frac{ {a}^{m} }{ {a}^{n} }  =  {a}^{m - n}
We apply this property to obtain;



\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  3 \times   {m}^{5 - 3}  \times  {n}^{5}


\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  3  {m}^{2} {n}^{5}

5 0
3 years ago
Read 2 more answers
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kodGreya [7K]
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