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3 years ago

Me. Fuller has 8/3 pies left over from her party. How can you write the number of pies she has left over as a mixed number?

Mathematics

2 answers:

zysi [14]3 years ago

7 0

The answer would be 2 2/3

zvonat [6]3 years ago

6 0

You could say that, "Mr.Fuller has 2 2/3 pies left over from his party.

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Which of these statements is correct? A) the distance between the points (-2, -9) and (9, 3) is 11 units B) the distance between

siniylev [52]

The answer is C The distance between the points (15,6) and (21,22)

4 0

3 years ago

Math- Differentiation . Could you help me to solve this question?

Arlecino [84]

Answer:

Step-by-step explanation:

Hello, first of all we can find a value for f(1)

$xf(x)+f(x^2)=2 \\\\\text{So for x = 1, it gives}\\\\f(1)+f(1^2)=f(1)+f(1)=2f(1)=2\\\\ f(1) =1$

And we can get the derivative of the equation so.

$(uv)'=u'v+uv' \text{ and } \dfrac{df(x^2)}{dx}=2xf'(x^2) \text{ so we can write}\\\\f(x)+xf'(x)+2xf'(x^2)=0\\\\\text{And then, for x = 1}\\\\f(1)+f'(1)+2f'(1)=0\\\\ f(1)+3f'(1)=0\\\\ 3f'(1)=-f(1)=-1\\\\\large \boxed{ f'(1)=-\dfrac{1}{3} }$

Thank you

4 0

2 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Mice21 [21]

Answer:

C=12

Step-by-step explanation:

2x12=24

3x12=36

5x12=60

7 0

2 years ago

Susan will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $70 and costs an ad

swat32

Answer:

350 miles

Step-by-step explanation:

Let x represent the miles driven

The cost with the first plan will be represented by 0.40x + 70

The second plan will be represented by 0.60x

Set these 2 expressions equal to each other and solve for x:

0.40x + 70 = 0.60x

70 = 0.20x

350 = x

So, Susan will have to drive 350 miles for the cost to be the same

4 0

3 years ago

Determine the factors of x2 − 7x − 10. (5 points) a (x + 2)(x − 5) b Prime c (x − 2)(x + 5) d (x + 10)(x − 1)

Savatey [412]

For this case we must factor the following expression:

$x ^ 2-7x-10$

To factor, we must find two numbers that when added together give -7 and when multiplied by -10.

It is observed that there are not two whole numbers that comply with the aforementioned.

Thus, the following equation applies:

$x = \frac {-b \pm\sqrt{b ^ 2-4 (a) (c)}} {2 (a)}$

Where:

$a = 1\\b = -7\\c = -10$

We replace:

$x = \frac {- (- 7) \pm \sqrt {(- 7) ^ 2-4 (1) (- 10)}} {2 (1)}\\x = \frac {7 \pm \sqrt {49 + 40}} {2}\\x = \frac {7 \sqrt {89}} {2}$

So, the roots are:

$x_ {1} =\frac {7+ \sqrt {89}} {2}\\x_ {2} =\frac {7- \sqrt {89}} {2}$

Answer:

$x_ {1} =\frac {7+ \sqrt {89}} {2}\\x_ {2} =\frac {7- \sqrt {89}} {2}$

6 0

3 years ago