Answer: 15
Step-by-step explanation:
(r+1)th term of
is given by:-

For
, n= 6

![=\ \dfrac{6!}{4!2!}a^4b^2\ \ \ [^nC_r=\dfrac{n!}{r!(n-r)!}]\\\\=\dfrac{6\times5\times4!}{4!\times2}a^4b^2\\\\=3\times5a^4b^2\\\\ =15a^4b^2](https://tex.z-dn.net/?f=%3D%5C%20%5Cdfrac%7B6%21%7D%7B4%212%21%7Da%5E4b%5E2%5C%20%5C%20%5C%20%5B%5EnC_r%3D%5Cdfrac%7Bn%21%7D%7Br%21%28n-r%29%21%7D%5D%5C%5C%5C%5C%3D%5Cdfrac%7B6%5Ctimes5%5Ctimes4%21%7D%7B4%21%5Ctimes2%7Da%5E4b%5E2%5C%5C%5C%5C%3D3%5Ctimes5a%5E4b%5E2%5C%5C%5C%5C%20%3D15a%5E4b%5E2)
Hence, the coefficient of the third term in the binomial expansion of
is 15.
Solution: f(18.5)=31.47
Step by step solution:
I started by making an equation in slope intercept form- I found the slope, 28/17, with the points (4, 17) and (12.5, 31). Then I found the y intercept, 1, with the point (4, 17). So the equation is y=28/17x+1. Then I just plugged 18.5 where the x is and solved for y
28/17(18.5)+1=y
28/17(37/2)+1=y
1036/34+1= y
30.47+1=y
y=31.47
Keep in mind that 1036/34 is not exactly 30.47 but that 30.47 was rounded to the nearest hundredth
Hope this helps :)
A = amount
.01a + .05a + .1a = 1.28
Combine like terms.
.16a = 1.28
Divide both sides by .16.
a = 8
8 * 3 = 24
There are 24 coins in the wallet.
-4 is what you put on both sides Bc it’s half of b
Answer:
No, because the ratios of the sides that form the vertex angles are the same, but the vertex angles may not be congruent.
Step-by-step explanation:
I just took the quick check