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elixir [45]
3 years ago
6

PLZZZZZZ HeLp

Mathematics
1 answer:
-BARSIC- [3]3 years ago
8 0

Answer:

Its False

Step-by-step explanation:

i hope its right

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In the diagram below, BE ~ BC, mLC = 32° and m/BFD = 103°. Find<br> m
steposvetlana [31]

Answer:

Here's a rainbow of logic.

Step-by-step explanation:

5 0
2 years ago
ملی
bonufazy [111]

Answer:

Rs 75,000

Step-by-step explanation:

Let the total value of property be x

If one-fifth of that is given to son

property with son = 1/5 of total value of property = 1/5 of x = x/5

If one-third of that is given to daughter

property with daughter = 1/3 of total value of property = 1/3 of x = x/3

remaining property after giving the portions to son and daughter

= total value of property - property with son -property with daughter

= x - x/5 - x/3

taking LCM of 5 and 3 (15)

= (15x - 3x - 5x)/15

= 7x/15

Given that remaining property was given to wife

property with wife = 7x/15

it is given that wife got 35000 Rs

thus,

7x/15 = 35,000

7x = 35,000*15 = 525,000

x =  525,000/7 = 75,000

Thus, total worth of property =Rs 75,000 Answer

4 0
3 years ago
Need help with this one!!!
DaniilM [7]
\bf (2x^2)^4(5x^6)\impliedby \textit{distributing the exponent}&#10;\\\\\\&#10;2^4x^{2\cdot 4}5x^6\implies 2^4\cdot 5x^{2\cdot 4}x^6\implies 16\cdot 5x^8x^6\implies 80x^{8+6}&#10;\\\\\\&#10;80x^{14}
8 0
3 years ago
What is the answer for -2/5(n + 3) = 10?
adell [148]

Answer: n=-28

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
HI PLEASE HELP ME WITH MY CALCULUS 1 HW? I AM REALLY STUCK. I need help with parts d,e,g.
asambeis [7]

(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when t=0 and t=3, and because the velocity function is continuous, you need only check the sign of v(t) for values on the intervals (0, 3) and (3, 6).

We have, for instance v(1)\approx-0.91 and v(4)\approx0.91>0, which means the particle is moving the positive direction for 3, or the interval (3, 6).

(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:

\displaystyle\int_0^6|v(t)|\,\mathrm dt=\int_0^3-v(t)\,\mathrm dt+\int_3^6v(t)\,\mathrm dt

which follows from the definition of absolute value. In particular, if x is negative, then |x|=-x.

The total distance traveled is then 4 ft.

(g) Acceleration is the rate of change of velocity, so a(t) is the derivative of v(t):

a(t)=v'(t)=-\dfrac{\pi^2}9\cos\left(\dfrac{\pi t}3\right)

Compute the acceleration at t=4 seconds:

a(t)=\dfrac{\pi^2}{18}\dfrac{\rm ft}{\mathrm s^2}

(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)

6 0
3 years ago
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