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ladessa [460]
2 years ago
12

You have a 12 volt battery and placed across a 6 ohm resistor, what will the current be?​

Physics
2 answers:
QveST [7]2 years ago
8 0

Answer:

i hope it help

Explanation:

It's possible to step 12 volts down to 6 volts by incorporating a pair of 10,000-ohm resistors into the circuit. Cut two lengths of wire, and strip each wire of 1/2 inch of insulation at each end. Attach one end of the first wire to the positive terminal on the power supply.

scoray [572]2 years ago
4 0

Answer:

Two

Explanation:

Volt = Current* Resistance

Current = Volt\Resistance

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<em></em>

Time = (450 km) / (100 m/s)

Time = (450,000 m) / (100 m/s)

Time = <em>4500 seconds </em>(that's 75 minutes)

Note:

This is about HALF the speed of the passenger jet you fly in when you go to visit Grandma for Christmas.

If the International Space Station flew at this speed, it would immediately go ker-PLUNK into the ocean.

The speed of the International Space Station in its orbit is more like 3,100 m/s, not 100 m/s.

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2. Suppose that a parallel-plate capacitor has circular plates with radius R = 30 mm and a plate separation of d = 5.0 mm. Suppo
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Answer:

The maximum value of the induced magnetic field is 2.901\times10^{-13}\ T.

Explanation:

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Radius of plate = 30 mm

Separation = 5.0 mm

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We need to calculate the angular frequency

Using formula of angular frequency

\omega=2\pi f

Put the value into the formula

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When r>R, the magnetic field is inversely proportional to the r.

We need to calculate the maximum value of the induced magnetic field that occurs at r = R

Using formula of magnetic filed

B_{max}=\dfrac{\mu_{0}\epsilon_{0}R^2\timesV_{max}\times\omega}{2rd}

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d = plate separation

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Put the value into the formula

B_{max}=\dfrac{4\pi\times10^{-7}\times8.85\times10^{-12}\times(30\times10^{-3})^2\times100\times376.9}{2\times130\times10^{-3}\times5.0\times10^{-3}}

B_{max}=2.901\times10^{-13}\ T

Hence, The maximum value of the induced magnetic field is 2.901\times10^{-13}\ T.

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