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Harman [31]
4 years ago
11

Two aces are missing from an otherwise normal deck of cards. If a card is selected at random from the deck, is this the probabil

ity that the selected card will be an ace?
Mathematics
2 answers:
Anton [14]4 years ago
6 0
The ratio is 2:50 (Reduced 1:25) I hope this helped ^^
Andre45 [30]4 years ago
4 0
There are 52 cards in a deck. If 2 are missing then there are 50 cards.

The chance of getting an ace is 2:50

50/50 chance it is either you do or you don't!
Hope this helps!
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Write the numerical expression in words two different ways. 7/ (10-3)
MissTica

Answer:

seven divided by the difference of ten and three

seven over the difference of ten and three

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3 years ago
At the hardware store, you purchased a box of nails for 17 dollar. You had a coupon that took off 20% from the nails. Sales tax
Vikentia [17]
(17-.2(17))+(17+.06(17))

5 0
3 years ago
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A set of ordered pairs is called ordered pairs is called
Amiraneli [1.4K]

A set of ordered pairs is called a relation. The set of all first components of the ordered pairs of a relation is the domain of the relation, and the set of all second components of the ordered pairs is the range of the relation. :)

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3 years ago
How do you write 40.545 in word form
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3 years ago
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triangle AMY ~ MEG , AM = 5 MY=7 AY =3. MEG IS A DILATION of AMY by a scale facyor of 1/3. fimd the perimeter of MEG.
Mademuasel [1]

Answer:

7

Explanation:

From the question, we're told that triangles AMY and MEG are similar. If triangle AMY has sides AM = 5, MY = 7, and AY = 3 then we can find the side lengths of triangle MEG since we're told from the question that it is a dilation of AMY by a scale factor of 1/3.

So all we need to is multiply the corresponding sides of AMY by 1/3, so we'll have;

\begin{gathered} ME=5\ast\frac{1}{3}=\frac{5}{3} \\ EG=7\ast\frac{1}{3}=\frac{7}{3} \\ MG=3\ast\frac{1}{3}=3 \end{gathered}

We can then go ahead and find the perimeter of MEG. Note that to find the perimeter of a triangle, we add all the length of its sides;

\begin{gathered} \text{Perimeter of MEG}=\frac{5}{3}+\frac{7}{3}+3 \\ =\frac{5+7+9}{3} \\ =\frac{21}{3} \\ =7 \end{gathered}

The perimeter of MEG is 7.

6 0
1 year ago
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