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xenn [34]
3 years ago
12

Determine if each factor is biotic or abiotic.

Physics
2 answers:
aliina [53]3 years ago
6 0

Answer: Biotic=dead tree,grasshopper,fungus/Abiotic= everything else

Explanation:

makkiz [27]3 years ago
3 0

Answer:Biotic=dead tree,grasshopper,fungus Abiotic= pond water ,temperature, soil

Explanation: got it right

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What is the minimum value of the friction coefficient between the boxes that will keep them from slipping when the 100 N force i
CaHeK987 [17]

Answer:

The friction coefficient's minimum value will be "0.173".

Explanation:

The given query seems to be incomplete. Below is the attached file of the complete question.

According to the question,

(a)

The net friction force's magnitude will be:

⇒ F_{net}=ma

           =5\times 1.7

           =8.5 \ N

(b)

For m₃,

⇒ ma=\mu m_3 g

Or,

⇒    \mu=\frac{a}{g}

          =\frac{1.7}{9.8}

          =0.173

5 0
3 years ago
Which will be attracted to (or repelled by) a magnet​
Tju [1.3M]

Answer:

An Iron horseshoe , A copper wire carrying current, Another magnet

3 0
4 years ago
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Which equation expresses the conservation of mechanical energy in a system where the only forms of mechanical energy are kinetic
scoundrel [369]
HI
I think the answer is:
mgh×1/2 mv2=constant.
hope it helps.
7 0
3 years ago
Scientists are constantly exploring the universe, looking for new planets that support life similar to the life on
Molodets [167]
The answer would be “B” because humans would need water, protection from radiation so we don’t melt or burn to death lol, and a gaseous atmosphere because we would need oxygen.
6 0
3 years ago
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Air "breaks down" when the electric field strength reaches 3 × 106 n/c, causing a spark. A parallel-plate capacitor is made from
Lera25 [3.4K]

Electric field between the plates of parallel plate capacitor is given as

E = \frac{Q}{A\epsilon_0}

here area of plates of capacitor is given as

A = 0.055 * 0.055

A = 3.025 * 10^{-3}

also the maximum field strength is given as

E = 3 * 10^6 N/C

now we will plug in all data to find the maximum possible charge on capacitor plates

3 * 10^6 = \frac{Q}{3.025 * 10^{-3}*8.85 * 10^{-12}}

Q = 8.03 * 10^{-8} C

so the maximum charge that plate will hold will be given by above

3 0
3 years ago
Read 2 more answers
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