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Crank
3 years ago
14

Express each of the following in ms -1 a) 18kmh-1​

Physics
1 answer:
vovangra [49]3 years ago
3 0
1km=1000m; 1hr=3600secs
1km/hr=1000/3600= 5/18m/sec
To convert km/hr into m/sec, multiply the number by 5 and then divide it by 18.

18kmh-1= 18•5=90
90/18=5
5ms-1
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What kind of energy involves the flow of positive charges?
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A 4 kg box is on a frictionless 35° slope and is connected via a massless string over a massless, frictionless pulley to a hangi
Anarel [89]

Answer:

(a) 19.62 N

(b) Box moves down the slope

(c) 24.43 N

Explanation:

(a)  

2 Kg box  causes tension

T=mgwhere m is mass, g is gravitational force taken as 9.81T=2*9.81 =19.62 N  (b)  Block mass of 4 Kg  [tex]T'-mg sin \theta=0 hence T'=mg sin \theta where m is mass and g is gravitational force  

T'=4*9.81 sin 35= 22.5071 N  

Since T' is greater than mg sin\theta , then the box moves down the slope  

(c)  

Acceleration a= \frac {forward   force-backward   force}{Total mass}= \frac {mg sin \theta -mg}{m1 + m2}  

a= \frac {22.51-19.62}{2+4}=0.48

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7 0
3 years ago
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4 years ago
78 grams of a radioactive nuclei X undergoes radioactive decay. The half-life of X is 4.7 minutes. After 16.5 minutes, the remai
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<u>Answer:</u> The remaining sample of X is 6.9 grams.

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t_{1/2}=\frac{0.693}{k}

We are given:

t_{1/2}=4.7min

Putting values in above equation, we get:

k=\frac{0.693}{4.7min}=0.147min^{-1}

The equation used to calculate time period follows:

N=N_o\times e^{-k\times t}

where,

N_o = initial mass of sample X = 78 g

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Putting values in above equation, we get:

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Hence, the remaining amount of sample X is 6.9 g

4 0
4 years ago
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