The formula for maximum distance is
X = (V^2 / g) * sin (2 * theta)
10 = (V^2 / 9.8) * sin (2 * 20)
10 = (V^2 / 9.0) * sin(40)
10 = (V^2 / 9.8) * 0.324
v^2 = (10 / 0.324) * 9.8
V^2 = 302.47
v = 17.39 meters/sec (takeoff speed)
The horizontal speed is = Takeoff Speed * Cos(20) = 17.39 * 0.910 = 16.341 meters / sec
An object is thrown horizontally from the open
window of a building. If the initial speed of the
object is 20 m/s and it hits the ground 2.0 s later,
from what height was it thrown? (Neglect air
resistance and assume the ground is level.)
Initial vertical velocity = 0
formula: s = ut + (1/2)*g*t^2
s = 0 + 1/2*9.8*2^2
s = 9.8*2 = 19.6 m
The correct answer is: acceleration.
In fact, the slope of the graph of velocity versus time corresponds to the ratio between the variation of v and the variation of t:

But this is exactly the definition of acceleration:

, so acceleration is the correct answer.
The average speed between 0 h and 2.340 h is 6.97 Km/h
Average speed is defined as the total distance travelled divided by the total time taken to cover the distance.

With the above formula, we can obtain the average speed between 0 h and 2.340 h as illustrated below:
- Total time = 2.340 – 0 = 2.340 h
- Total distance = 16.3 – 0 = 16.3 Km
- Average speed =?

Learn more about average speed: brainly.com/question/24884027
Answer:
What table I don’t see any table