Answer:
east of south
Explanation:
Given:
- distance of the person form the initial position,
- direction of the person from the initial position,
north of east
- distance supposed to travel form the initial position,
- direction supposed to travel from the initial position, due North
<u>Now refer the schematic for visualization of situation:</u>
...............(1)
.................(2)
<u>Now the direction of the desired position with respect to south:</u>
east of south
<u>Now the distance from the current position to the desired position:</u>
Answer:
0.0786
Explanation:
zero after the decimal place is not a significant figure since it comes before the real integer "7".
"5 " in ten thousandth place is rounded off to "6" because the next digit is also another "5",
so we get the three sfg 0.0786
Answer:
The angular speed after 6s is 
.
Explanation:
The equation
relates the moment of inertia 
of a rigid body, and its angular acceleration 
, with the force applied 
at a distance 
from the axis of rotation.
In our case, the force applied is 
, at a distance 
, to a ring with the moment of inertia of 
; therefore, the angular acceleration is
Therefore, the angular speed 
which is
after 6 seconds is
Answer
given,
ω₁ = 0 rev/s
ω₂ = 6 rev/s
t = 11 s
Using equation of rotational motion
The angular acceleration is
ωf - ωi = α t
11 α = 6 - 0
= 0.545 rev/s²
The angular displacement
θ₁= ωi t + (1/2) α t²
θ₁= 0 + (1/2) (0.545)(11)^2
θ₁= 33 rev
case 2
ω₁ = 6 rev/s
ω₂ = 0 rev/s
t = 14 s
Using equation of rotational motion
The angular acceleration is
ωf - ωi = α t
14 α = 0 - 6
= - 0.428 rev/s²
The angular displacement
θ₂= ωi t + (1/2) α t²
θ₂= 6 x 14 + (1/2) (-0.428)(14)^2
θ₂= 42 rev
total revolution in 25 s is equal to
θ = θ₁ + θ₂
θ = 33 + 42
θ = 75 rev
