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AysviL [449]
4 years ago
7

You and a friend are studying late at night. There are three 110 W light bulbs and a radio with an internal resistance of 56.0 Ω

plugged into the living room electrical outlets. You decide to have a break and have a snack, turning on the pop-corn machine that draws 7.00 A. How much electrical power are you using? Data: Assume the electric company provide you with 110 V potential difference.
Physics
1 answer:
Sliva [168]4 years ago
8 0

Answer:

The total electrical power we are using is: 1316 W.

Explanation:

Using the ohm´s law V=I*R and the formula for calculate the electrical power, we can find the total electrical power that we are using. First we need to find each electrical power that is using every single component, so the radio power is:I=\frac{V}{R}=\frac{110 (v)}{56(ohms)}=1.96(A), so the radio power is: P=I*V=1.96(A)*110(v)=216(W), then we find the pop-corn machine power as: P=I*V=7(A)*110(v)=770(W) and finally there are three light bulbs of 110(W) so: P=3*110(W)=330(W) and the total electrical power is the adding up every single power so that: P=330(W)+770(W)+216(W)=1316(W).

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A batter hits two baseballs with the same force.One hits the ground near third base.The other is a home run out of the park.Wher
andrezito [222]

The formula for work is:

W = F * d  Where W is work, F is Force, and d is distance.

Without doing any math, it can be seen from the equation that work is directly proportional to the force applied and the distance it travels.  The homerun hit both traveled more distance and had a grater force applied to it in order to achieve this distance (assuming both baseballs weighed the same).  Based on this reasoning, it is valid to conclude that the baseball which was a homerun was the hit that accomplished more work.

5 0
3 years ago
A star is estimated to be 4.8 km away from the earth. When we see this star in the night sky how old is the image. Let the speed
andre [41]

Time = distance / speed

Time = (4,800 meters) / (3 x 10⁸ m/s)

<em>Time = 0.000016 second</em>

This number is not one of the choices on the list.  My hunch is that you copied the distance wrong.

If the estimated distance to the star is actually 4.8 x 10¹⁵ km, instead of 4.8 km, then the answer would be close to 500 years <em>(B)</em>.

There's no way a star can be "4.8 km away from the Earth".  You can <em>walk</em> that far in about an hour, and passenger jet airplanes fly <em>twice</em> as far as that away from the Earth !

5 0
3 years ago
When one tectonic plate moves underneath another, what is occurring?
alexdok [17]
The answer is A. subduction
7 0
3 years ago
Janelle stands on a balcony, two stories above Michael. She throws one ball straight up and one ball straight down, but both wit
antoniya [11.8K]

Answer:

Both balls have the same speed.

Explanation:

Janelle throws the two balls from the same height, with the same speed. Both balls will have the same potential and kinetic energy. Energy must be conserved. When the balls pass Michael, again they must have the same potential and kinetic energy.

4 0
3 years ago
An 8.75 kg point mass and a 14.0 kg point mass are held in place 50.0 cm apart. A particle of mass m is released from a point be
marysya [2.9K]

Answer

given,

mass of the = m₁ = 8.75 Kg

another mass of the object = m₂ = 14 Kg

distance between them = 50 cm

R₁ = 17 cm

R₂ = 50 -17 = 33 cm

a) Force applied due to the Mass 8.75  in +ve x- direction

F_1 = \dfrac{GM_1 m}{R_1^2}

F_1 = \dfrac{6.67\times 10^{-11} \times 8.75\ m}{0.17^2}

F_1 = 2.019\times 10^{8}\ m

Force applied due to mass 14 Kg in -ve x-direction

F_2 = \dfrac{GM_2 m}{R_2^2}

F_2 = \dfrac{6.67\times 10^{-11} \times 14\ m}{0.33^2}

F_2 = 0.857\times 10^{8}\ m

net force

F = F₁ + F₂

F = 2.019\times 10^{8}\ m - 0.857\times 10^{8}\ m

F = 1.162\times 10^{8}\ m

Using newton second law

a = \dfrac{F}{m}

a = \dfrac{ 1.162\times 10^{8}\ m}{m}

a =1.162\times 10^{8} \ m/s^2

b) As the acceleration of mass comes out to be  +ve hence, the direction will be toward the mass of 8.75 Kg

6 0
3 years ago
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