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AysviL [449]
4 years ago
7

You and a friend are studying late at night. There are three 110 W light bulbs and a radio with an internal resistance of 56.0 Ω

plugged into the living room electrical outlets. You decide to have a break and have a snack, turning on the pop-corn machine that draws 7.00 A. How much electrical power are you using? Data: Assume the electric company provide you with 110 V potential difference.
Physics
1 answer:
Sliva [168]4 years ago
8 0

Answer:

The total electrical power we are using is: 1316 W.

Explanation:

Using the ohm´s law V=I*R and the formula for calculate the electrical power, we can find the total electrical power that we are using. First we need to find each electrical power that is using every single component, so the radio power is:I=\frac{V}{R}=\frac{110 (v)}{56(ohms)}=1.96(A), so the radio power is: P=I*V=1.96(A)*110(v)=216(W), then we find the pop-corn machine power as: P=I*V=7(A)*110(v)=770(W) and finally there are three light bulbs of 110(W) so: P=3*110(W)=330(W) and the total electrical power is the adding up every single power so that: P=330(W)+770(W)+216(W)=1316(W).

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Answer:

Rigorous exercise

Explanation:

For your heart rate is been around 100 bpm you should be doing a rigorous exercise . but if ain't doing any rigorous exercise and your heart rate is constantly above 100 bpm you should consult your doctor.

An average heart is between 60 bpm to 100 bpm.

6 0
3 years ago
Nikola Tesla and Thomas Edison were both pioneers when it came providing electricity to the people. Edison had hired the genius
Pepsi [2]

<u>Explanation:</u>

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3 years ago
A spring with a spring constant of 165 N/m is attached to a 2.0 kg mass and set into motion.
marin [14]

Explanation:

We have,

Spring constant of the spring, k = 165 N/m

Mass, m = 2 kg

It is required to find the period of the mass-spring system. For the spring mass system, the period is given by :

T=2\pi \sqrt{\dfrac{m}{k} }\\\\T=2\pi \sqrt{\dfrac{2}{165} }\\\\T=0.69\ s

The frequency of vibration is reciprocal of its time period. So,

f=\dfrac{1}{T}\\\\f=\dfrac{1}{0.69}\\\\f=1.44\ Hz

So, the period of the mass-spring system is 0.69 s and frequency is 1.44 Hz.

3 0
4 years ago
Please help on this one?
vova2212 [387]

Answer: The system internal energy is 40 Joules.

Explanation: As suggested, the formula \Delta U = Q-W=(70-30)J = 40J should be used. 70 Joules worth of thermal energy are added, and the system does 30 Joules worth of work (energy expenditure).

7 0
3 years ago
Read 2 more answers
Please help!!
pantera1 [17]

Answer:

(a) The time the ball stays in the air is approximately 4.66 seconds

(b) The distance from the cannon at which the ball will hit the ground is approximately 83.18 meters

(c) The maximum altitude of the ball is approximately 26.62 m

Explanation:

The given parameters of the question are;

The initial velocity at which a baseball cannon fires balls, u = 29 m/s

The angle at which the cannon is tilted, θ = 52°

(a) The time duration the ball stays in the air is given by the time of flight of the projected ball as follows;

2 \cdot t = \dfrac{2 \cdot u \cdot sin (\theta)}{g}

Where;

t = The time it takes the baseball to reach maximum height

2·t = The total time of flight = The time the ball stays in the air

θ = The angle at which the ball is tilted = 52°

g = The acceleration due to gravity ≈ 9.81 m/s²

u = The initial velocity = 29 m/s

Therefore, we have;

2 \cdot t = \dfrac{2 \times 29 \ m/s\times sin (52^{\circ})}{9.81 \ m/s^2} \approx 4.66 \ s

The time the ball stays in the air, 2·t ≈ 4.66 seconds

(b) The distance from the cannon at which the ball will hit the ground is given by the horizontal range, 'R', of the projectile as follows;

Horizontal \ range, R = \dfrac{u^2 \cdot sin(2 \cdot \theta) }{g}

∴ The distance from the cannon at which the ball will hit the ground = R

Horizontal \ range, R = \dfrac{(29 \ (m/s))^2 \cdot sin(2 \times 52^{\circ}) }{9.81 \ m/s^2} \approx 83.18 \, m

The distance from the cannon at which the ball will hit the ground = R ≈ 83.18 meters

(c) The maximum altitude of the ball is equal to the maximum height reached by the ball, H, which is given as follows;

H = \dfrac{u^2 \cdot sin^2 (\theta)}{2 \cdot g}

Therefore, we have;

H = \dfrac{(29 \ m/s)^2 \times sin^2 (52^{\circ})}{2 \times 9.81 \ m/s^2} \approx 26.62 \ m

The maximum altitude of the ball ≈ 26.62 m

3 0
3 years ago
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