Make a model for the the ionic bonding of Al and Cl.
1 answer:
Answer:
ClAl
Explanation:
* = electron
Cl (17) * * * * * * *
Al (13) * * *
If one of aluminum's electrons were added to chlorine to make a full shell, still have 2 left over. So you need another:
Cl * * * * * * * * (full)
Cl * * * * * * *
Al * *
Still have another left over. Aluminum needs to lose another one of its valence electrons to be able to have a full shell. So you take another chlorine:
Cl * * * * * * * * (full)
Cl * * * * * * * * (full)
Cl * * * * * * *
Al *
You will eventuate with 3Cl and 1Al, or ClAl. Modeled above:
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1 mole of nitric acid produce 1 mole of ammonium nitrate.
moles in 5000 kg of ammonium nitrate :
( molecular mass of ammonium nitrate is 80 gm/mol )
So, number of moles of nitric acid required are also 62500 moles.
Mass of 62500 moles of nitric acid :
Hence, this is the required solution.