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EleoNora [17]
3 years ago
13

Help me real quick !!

Chemistry
1 answer:
Ksenya-84 [330]3 years ago
4 0

Answer:

yellow

if not sorry that's though the best answer

Explanation:

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If i have a 50 L container that holds 45 moles of gas at a temperature of 473 K, what is the pressure inside the container?
Furkat [3]

Answer:

The pressure inside the container is 34.97 atm

Explanation:

Given:

V=50L R= 0.0821LatmK^-1mol^-1

n= 45mol T= 473k

PV=nRT

P= nRT/V

= 45mol*0.0821Latmmol^-1K^-1*473K/ 50L

=34.95atm

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3 years ago
Explain why ply(ethene) can become a pollutant? ​
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What does the latent heat of vaporization represent?
Maru [420]
<h3>Answer:</h3>

<u>∅</u><u>C</u>. The amount of energy required to turn a mole of a liquid into a gas

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7 0
1 year ago
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Convert 0.54 km to dm
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6 0
3 years ago
In a study of the following reaction at 1200 K it was observed that when the equilibrium partial pressure of water vapor is 15.0
sp2606 [1]

Answer:

The value of K_p for this reaction at 1200 K is 4.066.

Explanation:

Partial pressure of water vapor at equilibrium = p^o_{H_2O}=15.0 Torr

Partial pressure of hydrogen gas at equilibrium = p^o_{H_2}=?

Total pressure of the system at equilibrium P = 36.3 Torr

Applying Dalton's law of partial pressure to determine the partial pressure of hydrogen gas at equilibrium:

P=p^o_{H_2O}+p^o_{H_2}

p^o_{H_2}=P-p^o_{H_2O}=36.3 Torr- 15.0 Torr = 21.3 Torr

3 Fe(s) 4 H_2O(g)\rightleftharpoons Fe_3O_4(s) 4 H_2(g)

The expression of K_p is given by:

K_p=\frac{(p^o_{H_2})^4}{(p^o_{H_2O})^4}

K_p=\frac{(21.3 Torr)^4}{(15.0 Torr)^4}=4.066

The value of K_p for this reaction at 1200 K is 4.066.

6 0
3 years ago
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