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1 answer:
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1. P(getting all head)=
2. Event: getting all head can happen in only one way: HHH
3. n(Sample space) can be calculated by
a. counting, a good ways to organize counting is drawing a tree diagram, CHECK THE PICTURE
or
b. There are 2 possible outcomes each time we throw the dice so 2*2*2=8 is the total number of outcomes, that is the number of the sample space.
4. So finally P(getting all head)=
2. Event: getting all head can happen in only one way: HHH
3. n(Sample space) can be calculated by
a. counting, a good ways to organize counting is drawing a tree diagram, CHECK THE PICTURE
or
b. There are 2 possible outcomes each time we throw the dice so 2*2*2=8 is the total number of outcomes, that is the number of the sample space.
4. So finally P(getting all head)=
Answer:
The solution of the given equations
x =4 , y = 1
Step-by-step explanation:
<u>Explanation</u>:-
<u>Step(l</u>):-
Given the system of equations -5x+13y = -7 ..(l)
5x+4y=24 ..(ll)
<u>Step(ll)</u>
Adding (l) and (ll) equations and cancelling '5x' terms we get
13y+4y = -7 +24
17y = 17
dividing '17' on both sides, we get
y=1
<u>Step(lll):-</u>
Substitute y=1 in equation (l) , we get
-5x+13y = -7
-5x + 13(1) = -7
subtracting '13' on both sides, we get
-5x +13 -13= -7 -13
-5x = -20
Dividing '-5' on both sides, we get
x = 4
<u>Conclusion</u>:-
The solution of the given equations
x =4 , y = 1