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Ivan
3 years ago
10

Simplify 3(2x^4*y^5)^2/(6x^3*y^3)^6

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
7 0

\dfrac{3(2x^4y^5)^2}{(6x^3y^3)^6}\qquad\text{use}\ (ab)^n=a^nb^n\ \text{and}\ (a^n)^m=a^{nm}\\\\=\dfrac{3(2^2)(x^4)^2(y^5)^2}{6^6(x^3)^6(y^3)^6}=\dfrac{3(4)x^8y^{10}}{46656x^{18}y^{18}}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\dfrac{12x^8y^{10}}{46656x^8x^{10}y^{10}y^8}=\dfrac{1}{3888x^{10}y^8}

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sp2606 [1]

Answer:

length=4 1/4

Step-by-step explanation:

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2 years ago
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Rudik [331]

Answer:

B- 3,500.

Step-by-step explanation:

This is because 3,500 is the lowest number that can be rounded to 4,000.

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3,500 < 3,999 < 4,001.

That goes from smallest to largest numbers that round to 4,000.

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5 0
2 years ago
Pls help me this is due tomorrow
Anna [14]

Step-by-step explanation:

Claim: There's 14 Goats and 9 Chickens!!

Data:

Working with the Provided Information.

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The Chicken has Only a Pair Of Legs...Which is a total of 2 legs.... We say let its contribution be 2y

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BRINGING BOTH EQUATIONS TOGETHER.

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From Eqn i

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Substitute into eqn ii

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92 - 2y = 74

2y = 92 - 74

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This simply proves that there are 14 Goats and 9 Chickens!!!.

HAVE A GREAT DAY!

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3 years ago
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Answer:

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