A dipole is located at the origin, with charges +3 nC and -3 nCseparated by 4 μm. Consider a spherical Gaussian surfacecentered
1 answer:
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The distance covered by the proton is 48.4 m
Explanation:
The electric field produced by an electrically charged infinite plane is given by
where in this case,
is the surface charge density
is the vacuum permittivity
Substituting,
And the direction is towards the plane (because the charge is negative).
The electric force on the proton due to this field is
where
is the proton charge
Substituting,
where the direction is toward the plane.
Now we can calculate the proton's acceleration using Newton's second law:
where
is the proton mass
Substituting,
Now we can finally apply the following suvat equation for accelerated motion to find the distance travelled by the proton:
where
v = 0 is the final velocity
is the initial velocity
a is the acceleration
s is the distance covered
And solving for s,
Therefore, the closest answer is 48.4 m.
Learn more about accelerated motion:
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