If the resulting trajectory of the charged particle is a circle, what is ω, the angular frequency of the circular motion?
1 answer:
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Answer:
F_A = 8 F_B
Explanation:
The force exerted by the planet on each moon is given by the law of universal gravitation
F =
where M is the mass of the planet, m the mass of the moon and r the distance between its centers
let's apply this equation to our case
Moon A
the distance between the planet and the moon A is r and the mass of the moon is 2m
F_A = G \frac{2m M}{r^{2} }
Moon B
F_B = G \frac{m M}{(2r)^{2} }
F_B = G \frac{m M}{4 r^{2} }
the relationship between these forces is
F_B / F_A = = 1/8
F_A = 8 F_B
Answer:0.25 times
Explanation:
Given
Distance of satellite from earth surface=Radius of earth
Force on the satellite is F=mg'
where g'=acceleration due to gravity at that point
Distance from center of Earth=R+R=2R
Gravitational Force is given by
Force
Force on earth surface
Divide 1 and 2 we get