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4 years ago

What is the direction of the electric force exerted by paperclip 1 on paperclip 2?

1 answer:

6 0

In general, the electric force in an electric field is exerted outward from a positive atom, and inward for the negative atom. Therefore based on the figure you specified, we can say that the <span>electric force exerted by paperclip 1 on paperclip 2 is repulsive.</span>

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What are the divisions within a shell called

blsea [12.9K]

The divisions within an atom's shell are called subshells. This means that each shell consists of several subshells that are made up of orbitals. Each orbital consists of 1 or 2 electrons. The outermost shell of an atom is what we call the valence electrons, and they are what participate in chemical bonding.

5 0

3 years ago

Two positive point charges that are equal in magnitude are fixed in place, one at x = 0.00 m and the other at x = 1.00 m, on the

olga55 [171]

Answer:

0.5 m

Explanation:

Two charges each of magnitude q

Let the third charge is Q is placed at a distance x from the origin so that the charge is in equilibrium.

The force on Q due to q at origin is balanced by the charge on Q due to the charge q placed at x = 1 m.

So,

$\frac{KQq}{x^{2}}=\frac{KQq}{\left ( 1-x \right )^{2}}$

1 - x = x

1 = 2x

x = 0.5 m

Thus, the third charge is placed at x = 0.5 m .

6 0

3 years ago

Give two example for push or pull to change the state of motion of time two examples

dolphi86 [110]

Explanation:

An Example of push as a force would be to push on a swing. The force moves the swing in a particular direction and the harder that you push the further the swing will go.

An example of pull as a force would be opening a door. ...

An example of pressure as a force is when you push down on a pile of grapes. is this what you mean

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3 years ago

If one of two interacting charges is doubled, the force between the charges will _____________.

malfutka [58]

If one of two interacting charges is doubled, the force between the charges will double.

Explanation:

The force between two charges is given by Coulomb's law

$F=\frac{k q1 q2}{r^{2}}$

K=constant= 9 x 10⁹ N m²/C²

q1= charge on first particle

q2= charge on second particle

r= distance between the two charges

Now if the first charge is doubled,

we get $F'=\frac{k (2q1) q2}{r^{2}}$

F'= 2 F

Thus the force gets doubled.

4 0

3 years ago

Which is the best description for the lines I and k

hodyreva [135]

"Unknown, unspecified, unillustrated, undepicted, undescribed, undemonstrated, undefined, potentially non-existent."

6 0

3 years ago