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erastova [34]
3 years ago
11

Fill in the blank

Physics
1 answer:
pochemuha3 years ago
7 0

Explanation:

Your awnser is light year

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The built-up beam is formed by welding together the thin plates of thickness 5 mm. determine the location of the shear center o.
atroni [7]

Answer:

The location of the shear center o is 0.033 or 33 m

Explanation:

Solution

Recall that,

The moment of inertia of the section is =  I = 0.05 * 0.4 ^3 /12 + 0.005 * 0.2 ^3/12

= 30 * 10 ^ ⁻⁶ m⁴

Now,

The first moment of inertia is

Q =ῩA = [ (0.1 -x) + x/2] (0.005 * x)

= 0.5x * 10 ^⁻³ - 2.5 x * 10⁻³ x²

Thus,

The shear flow is,

q =  VQ/I

so,

P =  (0.5x * 10 ^⁻³ - 2.5 x * 10⁻³ x²)/ 30 * 10 ^⁻⁶

P = (16.67 x - 83. 33  x²)

The shear force resisted by the shorter web becomes

Vw,₂ = 2∫ = ₀.₁ and ₀ = P (16.67 x - 83. 33  x²) dx = 0.11x

Then,

We take the moment at a point A

∑Mₐ = 0

- ( p * e)- (Vw₂ * 0.3 ) = 0

e =  0.11 p * 0.3/p

which gives us 0.033 m

= 33 m

Therefore the location of the shear center o is 0.033 or 33 m

Note: Kindly find an attached diagram to the question given above as part of the explanation solved with it.

4 0
3 years ago
The ________________ of a machine is equal to the ratio of the work output to its input.
erastova [34]
Answer: mechanical efficieny.

Efficieny is also expressend as percent. The formula for mechanical efficiency as percent is the ratio work output to wor input times 100.

The ideal mechanical efficiency for a machine would be 1 or 100% which means that all the input work is converted into output work. But this is just an idealization as the friction and other losses of energy make it imposible to reach 100% efficiency in reality, so the mechanical efficiency of real machinces is less than 100% or 1.
5 0
3 years ago
You are standing 30 m from a window that is 30 m off the ground. Your friend tries to toss you something, but only throws it str
pochemuha

Answer:

minimum initial velocity is 21.35 m/s

Explanation:

given data

distance S = 30 m

height h = 30 m

maximum acceleration a = 2 m/s²

to find out

minimum initial velocity that your friend could have thrown the object to enable you to catch

solution

first we get here time with the help of second equation of motion

time = \sqrt{\frac{2h}{a} }  ..................1

put her value we get

time = \sqrt{\frac{2*30}{2} }

time = 5.477 second

and that is time which tossed object must be take so we apply here again second equation of motion that is

-S = ut - 0.5 × gt²   .......................2

-30 = u× 5.477 - 0.5 ×9.8×5.477²

solve it we get

u = 21.35 m/s

so minimum initial velocity is 21.35 m/s

3 0
3 years ago
Read 2 more answers
What is the displacement of an airplane that takes off and ascends 10,000 feet in the air but, to avoid turbulence, descends dow
sladkih [1.3K]
I think it’s A because ascending means going up 10,000 then descending is going down 2,000 so in all they are 8,000 feet above the ground
4 0
3 years ago
Read 2 more answers
5 x 10 to the power electron cross through the cross section of a wire per second. What is the magnitude of electric current pas
Rom4ik [11]

. She replaces a straight electrical

8 0
4 years ago
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