Answer:
When the motion of the fluid results due to natural means like the buoyancy effect, that is, the elevation of the warmer fluid and the fall of the cooling fluid is termed as natural convection. Boiling water is the everyday illustration of the natural convection, in the process, the passing of the heat takes place from the burner into the pot, and heats the water present at the bottom.
On the other hand, when the fluid is forced to flow in a tube or over the surface by external means like with the help of a fan or a pump is termed as forced convection. The use of a fan on a hot summer day is an everyday illustration of forced convection. An example of effective heat transfer is the sweat produced by our body. Therefore, when one switches off the fan, the air present around the body captivates the water vapor until it gets saturated. It takes place for some time and stops eventually, which makes one feel hotter.
At that time, when the fan is switched back again, the air surrounding the body starts to move again, without completely getting saturated, and thus, evaporation of the sweat takes place that also contains the heat of the body and one feels cooler.
Answer:
1. 15.71 g CO2
2. 38.19 % of efficiency
Explanation:
According to the balanced reaction (2 CO(g) + O2(g) → 2 CO2(g)), it is clear that the CO is the limitant reagent, because for every 2 moles of CO we are using only 1 mole of O2, so even if we have the same quantity for both reagents, not all of the O2 will be consumed. This means that we can just use the stoichiometric ratios of the CO and the CO2 to solve this question, and for that we need to convert the gram units into moles:
For CO:
C = 12.01 g/mol
O = 16 g/mol
CO = 28.01 g/mol
(10.0g CO) x (1 mol CO/28.01 g) = 0.3570 mol CO
For CO2:
C = 12.01 g/mol
O = 16 x 2 = 32 g/mol
CO2 = 44.01 g/mol
We now that for every 2 moles of CO we are going to get 2 moles of CO2, so we resolve as follows:
(0.3570 mol CO) x (2 mol CO2/2 mol CO) = 0.3570 moles CO2
We are obtaining 0.3570 moles of CO2 with the 10g of CO, now lets convert the CO2 moles into grams:
(0.3570 moles CO2) x (44.01 g/1 mol CO2) = 15.71 g CO2
Now for the efficiency question:
From the previous result, we know that if we produce 15.71 CO2 with all the 10g of CO used, we would have an efficiency of 100%. So to know what would that efficiency be if we would only produce 6g of CO2, we resolve as follows,
(6g / 15.71g) x 100 = 38.19 % of efficiency
Answer:
They could possibly make daily check ups to the research facility?
Cation means postive charged
answer is potassium.
being +1
