The answer to this question is A
n = 5
l = 0,1,2,3,4
ml = -4,-3,-2,-1,0,1,2,3,4,
ms = +1/2 and -1/2
Answer:
Explanation:
Assumptions
- They would ionize completely, or you must assume that.
- The volumes must be the same as well.
- 0.11M Cu(NO3)2 ===> 0.11MCu2+ + 0.22 NO3-
Note
The concentrations would merely add. All things change if the assumptions I've made are not true.
Answer:
Molecular formula = C₄H₆As₆Cu₄O₁₆
Explanation:
Given data:
Empirical formula = C₂H₃As₃Cu₂O₈
Molar mass of compound = 1013 g/mol
Molecular formula = ?
Solution:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
Empirical formula mass of C₂H₃As₃Cu₂O₈ is 506.897 g/mol
by putting values.
n = 1013 / 506.897
n = 2
Molecular formula = n (empirical formula)
Molecular formula = 2 (C₂H₃As₃Cu₂O₈)
Molecular formula = C₄H₆As₆Cu₄O₁₆
Answer:
The coronavirus has RNA?
Explanation:
Coronaviruses are important human and animal pathogens and contain an extraordinarily long (27-31 kb) RNA genome. Its RNA synthesis involves complex mechanisms of regulation, similar to those of DNA viruses. In this treatise, mouse hepatitis virus (MHV) is used as a model for the discussion of the mechanism of viral RNA synthesis. We show that MHV RNA synthesis requires interactions of multiple RNA components, which are likely mediated by protein-RNA and protein-protein, as well as RNA-RNA, interactions. This virus also provides a unique example of a discontinuous transcription mechanism, which involves a trans-acting RNA component. Finally, study of the cis-acting signals for the various steps of RNA synthesis revealed an insight into the regulation of viral RNA synthesis. This discussion suggests that the regulation of RNA synthesis in coronavirus is more complex than previously thought possible for RNA viruses. Coronavirus RNA transcription and replication may serve as a paradigm of RNA synthesis for RNA viruses in general.
