Given the system of equations One-third x minus two-thirds y = 7 and two-thirds x + 3 y = 11, which numbers can be multiplied by
2 answers:
You might be interested in
Answer:
In improper form your solution will be . As a mixed fraction it will be
.
Step-by-step explanation:
The first thing we want to do here is to simplify this expression. After doing so, " a " and " b " should be multiplied to result in a possible improper fraction,
- Apply exponential rule "
"
= - Combine fractions
and
= - Multiply the fractions, and simplify further
= =
- This is out simplified expression
Now that we have this simplified expression, we can see that a = , and b =
. Therefore, multiplying the two we should receive the improper fraction as follows,
=
- Note that this is in improper form. If you want your solution in a mixed fraction, it will be
.
Graph attached.
To graph by hand find the values at 1 and 3 by plugging it into the original function and drawing a line between the two.
2(1)-2 = 0 Point (1,0)
2(3)-2 = 4 Point (3,4)
To graph by hand find the values at 1 and 3 by plugging it into the original function and drawing a line between the two.
2(1)-2 = 0 Point (1,0)
2(3)-2 = 4 Point (3,4)