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3 years ago

Eight less than the sum of a number and 5 is 12. what is the number?

2 answers:

8 0

X+5-8=12
This is the equation you use. Then add 8 from both sides. You get x+5=20 then subtract 5 from both sides and you'll get x=15 which is the number. Hope it helps and mark as brainliest!

ankoles [38]3 years ago

5 0

X-8+5=12
x=12+8-5
x=15

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A set of angles has a ratio of 5 to 2. If the larger angle measures 105 degrees then what is the measure of the smaller angle

bekas [8.4K]

ratio 5:2

105, ___

5x = 105 → x = 21

2x = ____ → 2(21) = 42

Answer: 42°

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3 years ago

Read 2 more answers

Find c. Round to the nearest tenth

sergeinik [125]

Answer:

c = 0.5 cm

Step-by-step explanation:

Using the Sine rule in the triangle, then

= ( cross- multiply )

c × sin105° = 2 × sin15° ( divide both sides by sin105°

c = ≈ 0.5 cm ( to the nearest tenth )

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3 years ago

Find the volume of the cone. when r=6 and h=4 Either enter an exact answer in terms of pi or use 3.14 point and round your final

Ksenya-84 [330]

4*3.14=12.56
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3 years ago

A rancher wishes to build a fence to enclose a 2250 square yard rectangular field. Along one side the fence is to be made of hea

Bess [88]

Answer:

The least cost of fencing for the rancher is $1200

Step-by-step explanation:

Let x be the width and y the length of the rectangular field.

Let C the total cost of the rectangular field.

The side made of heavy duty material of length of x costs 16 dollars a yard. The three sides not made of heavy duty material cost $4 per yard, their side lengths are x, y, y. Thus

$C=4x+4y+4y+16x\\C=20x+8y$

We know that the total area of rectangular field should be 2250 square yards,

$x\cdot y=2250$

We can say that $y=\frac{2250}{x}$

Substituting into the total cost of the rectangular field, we get

$C=20x+8(\frac{2250}{x})\\\\C=20x+\frac{18000}{x}$

We have to figure out where the function is increasing and decreasing. Differentiating,

$\frac{d}{dx}C=\frac{d}{dx}\left(20x+\frac{18000}{x}\right)\\\\C'=20-\frac{18000}{x^2}$

Next, we find the critical points of the derivative

$20-\frac{18000}{x^2}=0\\\\20x^2-\frac{18000}{x^2}x^2=0\cdot \:x^2\\\\20x^2-18000=0\\\\20x^2-18000+18000=0+18000\\\\20x^2=18000\\\\\frac{20x^2}{20}=\frac{18000}{20}\\\\x^2=900\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{900},\:x=-\sqrt{900}\\\\x=30,\:x=-30$

Because the length is always positive the only point we take is $x=30$ . We thus test the intervals $(0, 30)$ and $(30, \infty)$

$C'(20)=20-\frac{18000}{20^2} = -25 < 0\\\\C'(40)= 20-\frac{18000}{20^2} = 8.75 >0$

we see that total cost function is decreasing on $(0, 30)$ and increasing on $(30, \infty)$ . Therefore, the minimum is attained at $x=30$ , so the minimal cost is

$C(30)=20(30)+\frac{18000}{30}\\C(30)=1200$

The least cost of fencing for the rancher is $1200

Here’s the diagram:

3 0

3 years ago

12 cm long 10 cm wide area square meters

Stels [109]

Answer:

120 sqcm, is the answer

6 0

2 years ago