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3 years ago

a city’s average temperature over five months is shown in the graph. which statement is not true of the data

Mathematics

1 answer:

mrs_skeptik [129]3 years ago

5 0

Answer: March to April shows the least increase of average temperature.

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Which of the following companies offers the greatest total employment compensation? Company A Company B Company C Company D Gros

san4es73 [151]

we know that

To find the company with the greatest total employee compensation package, adds each company's gross pay, paid insurance, and paid time off, then subtract the job expenses on the sum

Find the total employee compensation package for each company

Step $1$

Find the total employee compensation package for company A

$total\ employee\ compensation=gross\ pay\ +\ paid\ insurance\ +\ paid\ time\ -\ job\ expenses$

$total\ employee\ compensation=37,600+2,800+3,100-1,200\\ total\ employee\ compensation=42,300\ dollars$

Step $2$

Find the total employee compensation package for company B

$total\ employee\ compensation=gross\ pay\ +\ paid\ insurance\ +\ paid\ time\ -\ job\ expenses$

$total\ employee\ compensation=36,800+2,400+3,600-600\\ total\ employee\ compensation=42,200\ dollars$

Step $3$

Find the total employee compensation package for company C

$total\ employee\ compensation=gross\ pay\ +\ paid\ insurance\ +\ paid\ time\ -\ job\ expenses$

$total\ employee\ compensation=38,100+2,100+2,900-300\\ total\ employee\ compensation=42,800\ dollars$

Step $4$

Find the total employee compensation package for company D

$total\ employee\ compensation=gross\ pay\ +\ paid\ insurance\ +\ paid\ time\ -\ job\ expenses$

$total\ employee\ compensation=39,000+1,800+2,500-800\\ total\ employee\ compensation=42,500\ dollars$

therefore

the answer is

the company with the greatest total employee compensation package is the company C

8 0

2 years ago

Read 2 more answers

Question is in picture

Pachacha [2.7K]

Answer:

I don't understand what should i answer.

The only thing I undrestood was that this is a relation which can be a function.

5 0

2 years ago

15 points: can someone help me with this thank you. (all separate equations)

OLga [1]

Step-by-step explanation:

$6x+3y=12\qquad\text{subtract}\ 6x\ \text{from both sides}\\\\6x-6x+3y=12-6x\\\\3y=12-6x\qquad\text{divide both sides by 3}\\\\\dfrac{3y}{3}=\dfrac{12}{3}-\dfrac{6y}{3}\\\\\large\boxed{y=4-2y}\\\\===================$

$2p-k=3\qquad\text{subtract}\ 2p\ \text{from both sides}\\\\2p-2p-k=3-2p\\\\-k=3-2p\qquad\text{change the signs}\\\\k=-3+2p\\\\\large\boxed{k=2p-3}\\\\===================$

$6v-2w=10\qquad\text{subtract}\ 6v\ \text{from both sides}\\\\6v-6v-2w=10\\\\-2w=10-6v\qquad\text{divide both sides by (-2)}\\\\\dfrac{-2w}{-2}=\dfrac{10}{-2}-\dfrac{6v}{-2}\\\\w=-5+3v\\\\\large\boxed{w=3v-5}\\\\===================$