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charle [14.2K]
3 years ago
13

The first term of an arithmetic sequence is 2 and the fourth term is 11

Mathematics
1 answer:
dybincka [34]3 years ago
5 0

Answer:

The sequence has common difference 3, and its general nth term can be written as:

a_n=3\,n-1

Step-by-step explanation:

In order to define the sequence, we recall the formula for the nth term of an arithmetic sequence as:

a_n=a_1+(n-1)\,d

where "d" is the common difference for the sequence (our unknown in this case), and the nth term is our fourth term (n = 4) which equals 11, and the first term is 2:

a_n=a_1+(n-1)\,d\\11=2+(4-1)\,d\\9=3\,d\\d=9/3\\d=3

Therefore our sequence has common difference 3, and its general nth term can be written as:

a_n=2+(n-1)3\\a_n=3\,n-1

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The value of the constant 'k' in the factored form factorization the provided polynomial equation is 3.

<h3>What is polynomial equation?</h3>

Polynomial equations is the expression in which the highest power of the unknown variable is n (n is real number).

The factor of a polynomial is the terms in linear or equation form, which are when multiplied together, give the original polynomial equation as result.

The given polynomial equation in the problem is,

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The factor of the polynomial equation are given as,

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First find out the factors to compare and find the value of k.The above equation has the unknown variable x and the highest power of this unknown variable is 3.

Take out the highest common factor 2, which can divide each term of the above equation (2, 18, -18, -162). Thus,

2(x+ k)(x - k)(x +9)=2(x^3 +9x^2 - 9x - 81)

Take out the highest common factor to make the groups as,

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Use the property of difference of the square for the (x²-3²) term as,

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On comparing the two equation, we get the value of k as 3. Thus, the value of the constant 'k' in the factored form factorization the provided polynomial equation is 3.

Learn more about factor of polynomial here;

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