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Lesechka [4]
3 years ago
15

4) Ethanol has a density of 0.8 g/cm3. What is the mass of 225 cm3 of ethanol

Chemistry
1 answer:
AveGali [126]3 years ago
7 0

Answer:

\huge\boxed{\sf m = 180\  g}

Explanation:

<u>Given:</u>

Density = ρ = 0.8 g/cm³

Volume = V = 225 cm³

<u>Required:</u>

Mass = m = ?

<u>Formula:</u>

m = ρV

<u>Solution:</u>

m = (0.8)(225)

m = 180 g

\rule[225]{225}{2}

Hope this helped!

<h2>~AnonymousHelper1807</h2>
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Explanation:

1 literThe total of water is equal to 1000.0 g of water

we need to find the molality of a solution containing 10.0 g of dissolved in  Na₂S0₄1000.0 g of water

1. For that find the molar mass

Na:  2 x 22.99= 45.98

S:  32.07

O:  4 x 16= 64

The total molar mass is 142.05

We have to find the number of moles, y

To find the number of moles divide 10.0g by 142.05 g/mol.

So the number of moles is 0.0704 moles.

For the molarity, you need the number of moles divided by the volume. So, 0.0704 mol/1 L.

The molarity would end up being 0.0704 M

The molality of a solution containing 10.0 g of Na2SO4 dissolved in 1000.0 g of water is  0.0704 Mliter

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2 years ago
Write the balanced equation for the equilibrium reaction for the dissociation ofsilver chloride in water, and write the K expres
Marizza181 [45]

Answer:

See explanation

Explanation:

Hello there!

In this case, since the the concentrations are not given, and not even the Ksp, we can solve this problem by setting up the chemical equation, the equilibrium constant expression and the ICE table only:

AgCl(s)\rightleftharpoons Ag^+(aq)+Cl^-(aq)

Next, the equilibrium expression according to the produced aqueous species as the solid silver chloride is not involved in there:

Ksp=[Ag^+][Cl^-]

And therefore, the ICE table, in which x stands for the molar solubility of the silver chloride:

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I          -                   0             0

C        -                   +x           +x

E        -                    x             x

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Ksp=x^2

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Regards!

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<u>Explanation:</u>

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