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Hatshy [7]
3 years ago
10

Ralph conducted an experiment to study the effect of temperature change on the heart rate of

Chemistry
1 answer:
Irina-Kira [14]3 years ago
6 0

Answer:

c. Ralph's classmate observing Daphnia in water at 30oC, 32oC and 34oC

Explanation:

When we talk about replication, we actually mean, repetition of a scientific procedure carried out by another scientist and obtaining the same results as he/she previously did.

Replication is carried out under identical conditions as the first scientist did. If Ralph's classmate wants to replicate Ralph's work, then identical temperature conditions of 30oC, 32oC and 34oC must be used, hence the answer above.

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Complete and balance the following reactions ?<br> uo^2+ +cr2o^2-7 ــــــــــــــــ uo2+ +cr3+
motikmotik
I think the answer is Fe. Hope it help!
7 0
3 years ago
1(30%). A thin plate black body, insulated at the bottom is placed faced up in a room with wall temperatures of 30 C. Air at 0 C
ch4aika [34]

Explanation:

The given data is as follows.

         Heat transfer coefficient (h) = 12W/m^{2}.C

         Plate temperature (T_{1}) = 30 ^{o}C = 303 K

         Steady state temperature (T_{2}) = ?

Hence, formula applied for steady state is as follows.

       (h \times A \times \Delta T)_{air} = \sigma \times A \times (T^{4}_{1} - T^{4}_{2})_{plate}

Putting the given values into the above formula as follows.

       (h \times A \times \Delta T)_{air} = \sigma \times A \times (T^{4}_{1} - T^{4}_{2})_{plate}

        12 \times (T_{2} - 273) = 5.67 \times 10^{-8} \times [(30 + 273)^{4} - T^{4}_{2}]

                  T_{2} = 282.66 K

                              = (282.66 -273)^{o}C      

                              = 9.66 ^{o}C      

Thus, we can conclude that the steady state temperature will be 9.66 ^{o}C.

3 0
3 years ago
Select the correct answer. which substance in this redox reaction is the oxidizing agent? cu 2agno3 → 2ag cu(no3)2 a. n b. agno3
lana66690 [7]

AgNO₃ will act as the oxidising agent.

<h3><u>For the given chemical equation:</u></h3>

Cu + 2AgNO₃ →  2Ag + Cu(NO₃)₂

Half reactions for the given chemical reaction:

<u>Reducing agent:</u>

Cu → Cu²⁺ + 2e⁻

Copper is a reducing agent because it is losing 2 electrons, which causes an oxidation process.

<u>Oxidising Agent</u>:

Ag⁺ + e⁻ → Ag

The silver ion undergoes a reduction process and is regarded as an oxidizing agent since it is acquiring one electron per atom.

Hence, AgNO₃ is considered as an oxidizing agent and therefore the correct answer is Option B.

<h3><u>Oxidising and Reducing agents</u></h3>
  • An oxidizing agent is a substance that reduces itself after oxidizing another material. It passes through a reduction process in which it obtains electrons and the substance's oxidation state is decreased.
  • A reducing agent is a chemical that oxidizes after reducing another material. It passes through an oxidation process in which it loses electrons and the substance's oxidation state increases.

To know more about the process of Oxidation and Reduction, refer to:

brainly.com/question/4222605

#SPJ4

8 0
1 year ago
How are some mutations similar? Provide examples.
Hatshy [7]

Answer:

Mutations can be caused by high-energy sources such as radiation or by chemicals in the environment. They can also appear spontaneously during the replication of DNA. Mutations generally fall into two types: point mutations and chromosomal aberrations. In point mutations, one base pair is changed. A single mutation can have a large effect, but in many cases, evolutionary change is based on the accumulation of many mutations with small effects. Mutational effects can be beneficial, harmful, or neutral, depending on their context or location. Most non-neutral mutations are deleterious.

Have an awesome day friend! <3

3 0
3 years ago
Read 2 more answers
A hydrogen atom requires a minimum energy of 2.18×10^-18 J atom to remove an electron from its ground state level. Determine whe
frosja888 [35]
Just find the energy of the <span>blueviolet light with a wavelength of 434.0 nm using the formula:

E  = hc / lambda

E = energy
c= speed of light =  3 x 10^8 m/s
h = planck's constant =  6.6 x 10^{-34}  m^2 kg / s
lambda =  434 nm =  434 x 10^{-9} m

Putting these values (with appropriate units) in the above formula :

we get:  Energy, E = 4.5 x 10^{-19} J

E = 0.45 x 10^{-18} J

Now, the </span>minimum energy is 2.18×10^-{18} J but our energy is 0.45 x 10^{-18} J which is less.
<span>Means the electron will not be removed

</span>
5 0
3 years ago
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