The total mass is 10.57+6.96=17.53 g.
So, the percent by mass of magnesium is (10.57)/(17.53) * 100 = <u>60.3%</u>
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The percent by mass of oxygen is (6.96)/(17.53) * 100 = <u>39.7%</u>
2-Chlorobutane, 2-Bromo-3-methylbutane are chiral .
chiral condition - a compound is said to be chiral if it is surrounded by 4 different groups
I,IV are chiral
II,III are achiral
Molecular types with non-superposable mirror images are known as chiral molecules. The existence of an asymmetric carbon atom in a molecule is the characteristic that most frequently contributes to chirality. When referring to an object that cannot be superposed on its mirror counterpart, the adjective "chiral" is generally employed.
A corkscrew, golf clubs, scissors, and other chiral items all have a "handedness." Thus, one can get scissors and golf clubs that are designed for either hand. Gloves and shoes are also sold in pairs, a right and a left.
learn more about chiral molecules here:
brainly.com/question/28095208
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Answer: The distance is slightly less than 3.5 m
Explanation: assuming wall and target are the same thing, and the bullet has constant velocity, the bullet will travel 7 m in half a second, so half that distance is 3.5 m.
In reality, the bullet is decelerating (at an unknown rate) so the distance is slightly less than 3.5 m.
There is also a vertical velocity component, which means it hits the target/wall at an angle. The trajectory is such that it hits the wall above the shooter because the ricochet hits at ~the level at which it left the firearm.
If the wall was absent, the bullet would have described a parabola which brough it back to the initial level after 7m. This could be calculated, but it means that the actual distance between the shooter and the wall is slightly less than 3.5 m
In addition, the collision with the wall is not 100% elastic, so the velocity aftercthe ricochetvis further reduced.
A calculation would be complex because these confounding factors are not completely independent of each other, but all reduce the average velocity and therefore the distance.
Therefore it is only possible to say that the distance was somewhat less than 3.5 m
Answer:
D
Explanation:
What an interesting amusing question.
The formula for KE = 1/2 m v^2.
v implies that there is motion.
The answer you are looking for is the body of water that has 0 for v.
A cloud moves, so it is not the answer.
A hailstone moves until it hits the ground. I'm assuming it's either on it's way down or it is caught in some sort of updraft in a cumulonimbus cloud. So it has motion.
Same comment for a raindrop. It has a v until it hits the ground so I'm assuming it is not the answer.
I've never seen a puddle of water move. It can only evaporate. So of all your choices, this one (D) is likely the right answer.
