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3 years ago

How many mole are in 14.5 grams of neon please explain

Chemistry

1 answer:

a_sh-v [17]3 years ago

3 0

Answer:

0.725 moles

Explanation:

Use the mole = mass/mr equation to find the moles.

Mole = 14.5/20 (Neon's Mr) = 0.725 Moles

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A steel container filled with H₂ gas is at a pressure of 6.5 atm and a temperature of 22°C. If the container is placed near a fu

Yuki888 [10]

Answer: The new pressure is 7.1 atm

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1\text{ and }T_1$ are the initial pressure and temperature of the gas.

$P_2\text{ and }T_2$ are the final pressure and temperature of the gas.

We are given:

$P_1=6.5atm\\T_1=22^0C=(22+273)K=295K\\P_2=?\\T_2=50^0C=(50+273)K=323K$

Putting values in above equation, we get:

$\frac{6.5}{295}=\frac{P_2}{323}\\\\P_2=7.1$

Hence, the new pressure is 7.1 atm

8 0

3 years ago

Which of the following is NOT a variable property for a gas?

Alex_Xolod [135]

Mass, air has that. Since what fills up a balloon? A gas
Shape, it has no definite shape. This one is accurate, it has no definite shape, it takes the shape of the object it's in.
Volume, does air take up space? If it does then yep. Balloon example/
Density, yes it does, because it's tightly wounded up.

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5 0

4 years ago

Read 2 more answers

Abnormal cell division causes which health problem

Romashka-Z-Leto [24]

Chromosomes abnormalities often happen due to one or more of these:
Errors during of sex cells (meiosis)
Errors during of other cells(mitosis)
Substances that causes birth defects (teratogens)

3 0

3 years ago

Pentaborane−9 (B5H9) is a colorless, highly reactive liquid that will burst into flames when exposed to oxygen. The reaction is

mote1985 [20]

Answer : The heat released per gram of the compound reacted with oxygen is 71.915 kJ/g

Explanation :

Enthalpy change : It is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H^o$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]$

The equilibrium reaction follows:

$2B_5H_9(l)+12O_2(g)\rightleftharpoons 5B_2O_3(s)+9H_2O(l)$

The equation for the enthalpy change of the above reaction is:

$\Delta H^o_{rxn}=[(n_{(B_2O_3)}\times \Delta H^o_f_{(B_2O_3)})+(n_{(H_2O)}\times \Delta H^o_f_{(H_2O)})]-[(n_{(B_5H_9)}\times \Delta H^o_f_{(B_5H_9)})+(n_{(O_2)}\times \Delta H^o_f_{(O_2)})]$

We are given:

$\Delta H^o_f_{(B_5H_9(l))}=73.2kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(B_2O_3(s))}=-1271.94kJ/mol\\\Delta H^o_f_{(H_2O(l))}=-285.83kJ/mol$

Putting values in above equation, we get:

$\Delta H^o_{rxn}=[(5\times -1271.94)+(9\times -285.83)]-[(2\times 73.2)+(12\times 0)]=-9078.57kJ/mol$

Now we have to calculate the heat released per gram of the compound reacted with oxygen.

From the reaction we conclude that,

As, 2 moles of compound released heat = -9078.57 kJ

So, 1 moles of compound released heat = $\frac{-9078.57}{2}=-4539.28kJ$

For per gram of compound:

Molar mass of $B_5H_9$ = 63.12 g/mole

$\Delta H^o_{rxn}=\frac{-4539.28}{63.12}=-71.915kJ/g$

Therefore, the heat released per gram of the compound reacted with oxygen is 71.915 kJ/g

7 0

3 years ago

If a reaction ends with 5.5 grams of products, how many grams of reactants were required to start the reaction?

xz_007 [3.2K]

5.5 grams of reactants. According to the Law of Conservation of Mass, mass isn’t created or lost through any chemical changes, so the total mass should remain constant from the initial reactants to the final products.

5 0

3 years ago