for an object that is speeding up in the positive direction, what does the displacement vs. time graph look like?
2 answers:
Answer:
displacement vs time graph will look like a parabolic shaped graph
Explanation:
As we know that the displacement of an object is given by kinematics equation when object is moving with uniform acceleration
So we know that
now here since velocity is increasing in positive X direction as well as the acceleration is also in same direction then the displacement vs time graph must be a straight line graph
so we will have
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Answer:
95.9°
Explanation:
The diagram illustrating the action of the two forces on the object is given in the attached photo.
Using sine rule a/SineA = b/SineB, we can obtain the value of B° as shown in the attached photo as follow:
a/SineA = b/SineB,
83/Sine52 = 56/SineB
Cross multiply to express in linear form
83 x SineB = 56 x Sine52
Divide both side by 83
SineB = (56 x Sine52)/83
SineB = 0.5317
B = Sine^-1(0.5317)
B = 32.1°
Now, we can obtain the angle θ, between the two forces as shown in the attached photo as follow:
52° + B° + θ = 180° ( sum of angles in a triangle)
52° + 32.1° + θ = 180°
Collect like terms
θ = 180° - 52° - 32.1°
θ = 95.9°
Therefore, the angle between the two forces is 95.9°
