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Bogdan [553]
3 years ago
8

A lunar module weighs 12 metric tons on the surface of the Earth. How much work is done in propelling the module from the surfac

e of the moon to a height of 40 miles? Consider the radius of the moon to be 1100 miles (from the center of the moon) and its force of gravity to be one-sixth that of Earth. (Round your answer to the nearest integer.)
Physics
1 answer:
zhuklara [117]3 years ago
6 0

Answer:

W=76.55 miles.metric tons

Explanation:

Given that

Weight on the earth = 12 tons

So weight on the moon =12/6 = 2 tons

 ( because at moon g will become g/6)

As we know that

F=\dfrac{K}{x^2}

Here x= 1100 miles

F 2 tons

2=\dfrac{K}{1100^2}

So

K=2.4\times 10^6

We know that

Work = F. dx

W=\int_{x_1}^{x_2}F.dx

W=\int_{1100}^{1140}\dfrac{2.4\times 10^6}{x^2}.dx

W=-2.4\times 10^6\left[\dfrac{1}{x}\right]_{1100}^{1140}

W=-2.4\times 10^6\left[\dfrac{1}{1140}-\dfrac{1}{1100}\right]

W=76.55 miles.metric tons

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The peak magnetic field of the electromagnetic wave in the red part of the visible spectrum is 9.67 x 10⁻¹⁰ T.

<h3>Relationship between electric and magnetic field</h3>

The relationship between electric and magnetic field at a given peak electric field is given as;

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B₀ = E₀ / c

B₀ = (2.9) / (3 x 10⁹)

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At the end of the walk, the person's resultant displacement is 495.1 m at 63⁰ south of west.

<h3>What is resultant displacement?</h3>

The resultant displacement of an object is the change in position of the object. It can be described as the shortest distance connecting the final position of the object to the initial position of the object.

<h3>Net horizontal displacement </h3>

Path 1 = 40 m

Path 2 = 0 m

Path 3 = 110 m x cos(30) = 95.26 m

Path 4 = 180 m x cos(60) = 90 m

Total horizontal displacement, X = 40 m + 0 m + 95.26 m + 90 m = 225.26 m

<h3>Net vertical displacement </h3>

Path 1 = 0 m

Path 2 = 230 m

Path 3 = 110 m x sin(30) = 55 m

Path 4 = 180 m x sin(60) = 155.885 m

Total horizontal displacement, Y = 0 m + 230 m + 55 m + 155.885 m = 440.885 m

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R = 495.1 m

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θ =  63⁰

Thus, at the end of the walk, the person's resultant displacement is 495.1 m at 63⁰ south of west.

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Answer:

Explanation:

We shall apply law of conservation of momentum during the collision of ball A and B .

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