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3 years ago

15

molly works at an electronics store her last customer purchased a dvd player for $63.04 and five dvds for $58.27 including taxes

if the customer paid her with two $100 bills how much change would she give him

1 answer:

Alecsey [184]3 years ago

4 0

Answer:

$78.69

Step-by-step explanation:

63.04+58.27=121.31

200-121.31=78.69

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A die is thrown. What is the probability of getting 6?<br>(a) 0<br>b 1/6<br>c 1/2<br>d 1

Firdavs [7]

Answer:

1/6

Step-by-step explanation:

There are 6 sides on a die, labeled 1,2,3,4,5,6

P(6) = number of 6's / total numbers

= 1/6

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3 years ago

Find the output, k, when the input, t, is –7.<br> k = 10t -19

kupik [55]

Answer:

k = - 89

Step-by-step explanation:

To calculate the output, substitute t = - 7 into the equation for output, that is

k = 10(- 7) - 19 = - 70 - 19 = - 89

7 0

2 years ago

In 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hir

Ede4ka [16]

Answer:

Explained below.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}= p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

(a)

The sample selected is of size <em>n</em> = 450 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

$\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{450}}=0.0204$

So, the sampling distribution of sample proportion is $\hat p\sim N(0.75,0.0204^{2})$ .

(b)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

$P(p-0.04$

$=P(-1.96$

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.

(c)

The sample selected is of size <em>n</em> = 200 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

$\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{200}}=0.0306$

So, the sampling distribution of sample proportion is $\hat p\sim N(0.75,0.0306^{2})$ .

(d)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

$P(p-0.04$

$=P(-1.31$

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.

(e)

The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.

And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.

So, there is a gain in precision on increasing the sample size.

6 0

2 years ago

Stacy hits the jackpot one day at the gumball machine. She puts in a quarter and gets 444 gumballs rather than 111. The radius o

inn [45]

Answer: 3617.28 cubic millimeters.

Step-by-step explanation: I used the formula of a sphere since a gumball is a shape of a sphere and plugged the radius into the formula.

I got that the volume of a single gumball is 288π cubic millimeters.

Since there are 4 gumballs, i multiplied the volume by 4.

The total volume of the four gumballs add up to be 1152π .

Lastly, I multiplied 1152 by pi

and got the answer to be 3617.28 cubic millimeters

8 0

3 years ago

2 eight and eleven hundredths as a decimal

german

Answer:

28.11

Step-by-step explanation:

6 0

3 years ago