Answer: f^-1(x)=-7x+3 maybe ? i think
Step-by-step explanation:
Answer:
t3 = 8, t5 = 14
Step-by-step explanation:
t3 = 2 + (3-1) × 3
t3 = 2 + (2) × 3
t3 = 2 + 6
t3 = 8
t5 = 2 + (5-1) × 3
t5 = 2 + (4) × 3
t5 = 2 + 12
t5 = 14
Answer:
B. 0
Step-by-step explanation:
If you subtract the right side expression and simplify, you get ...
4/5(20x +5) -(16x -2) = 0
16x +4 -16x +2 = 0
6 = 0 . . . . . . . . . . . . false
There is no value of x that will make this true. There are no solutions.
Answer:
Find the linearization L(x,y) of the function at each point. f(x,y) = x2 + y2 + 1 a. (4,0) b. (2,0) a. L(x,y) = Find the linearization L(x,y,z) of the function f(x,y,z) = 1x2 + y2 +z2 at the points (7,0,0), (3,4,0), and (4,4,7). The linearization of f(x,y,z) at (7,0,0) is L(x,y,z)= (Type an exact answer, using radicals as needed.)
