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3 years ago

I don't quite understand this.

Mathematics

1 answer:

tresset_1 [31]3 years ago

7 0

Im not really sure if im correct, since I havent done this in a long time and i can barely see the screen, but you need to flip the photo, giving you A/B = S/P

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If your dinner bill was $80 and you left a 15% tip. How much money did you leave as a tip? What is your total bill cost?

nadya68 [22]

Answer: 92 dollars because 15% divided into 80 is 12 and add 80 to 12 and its 92

6 0

3 years ago

In circle O, the radius is 4, and the length of minor arc AB is 4.2 feet. Find the measure of minor arc AB to the nearest degree

Degger [83]

The formula for arc length is s=r*angle theta where s is the arc length, r is the radius, and angle theta is central angle formed by the arc in radians.

In this case, the angle would be s/r or 4.2/4 which is 1.05 radians. We have to convert this into degrees and so you would multiply 1.05 by (180/pi) which results in approximately 60 degrees. Remember, if you want to convert radians into degrees, the conversion factor is 180/pi and for degrees into radians, it is pi/180.

4 0

3 years ago

Read 2 more answers

-1/5(x-4) = -2<br><br> What is the solution

Viefleur [7K]

$\frac{ - 1}{5} (x - 4) = - 2$
ANSWER
$x = 14$

4 0

3 years ago

Which of the following are characteristics of the graph of the quadratic parent function

stich3 [128]

Answer:

Answer – A and B

A. It is a parabola

B. It is in quadrants I and II

The most simple quadratic function is y = x^2. The graph drawn for this function, y = x^2) is known as the graph of the quadratic parent function OR the parent function for parabolas. This graph has some few characteristics:

- It is the simplest parabola (Generally, the graph of any quadratic function is a parabola).

- It passes through the origin (0,0).

- It is contained in Quadrants I and II.

hope this helps!

8 0

3 years ago

3. Show that a circle with equation (x−2)^2+(y+3)^2=160 has two tangent lines with equations

Pepsi [2]

Answer:

see below

Step-by-step explanation:

A graphing calculator shows each of the lines intersect the circle in exactly one place, so is tangent.

Each of the given lines is written in point-slope form. Each has a slope of 1/3. We will call the point in its equation the "reference point" of each line. For the first line, it is (6, -15); for the second line it is (-2, 9).

The center of the circle is (2, -3), so the slope from the center to the reference point of each line is ...

line 1: (-15 -(-3))/(6 -2) = -12/4 = -3

line 2: (9 -(-3))/(-2-2) = 12/-4 = -3

These slopes are the negative reciprocal of the slope of each of the lines, so a segment from the circle center to the reference point of each line is perpendicular to the line.

The reference point of line 1 (6, -15) is on the circle:

(6 -2)^2 +(-15 +3)^2 = 16 +144 = 160

The reference point of line 2 (-2, 9) is on the circle:

(-2-2)^2 +(9 +3)^2 = 16 +144 = 160

So, the reference point of each line is on the circle and that point is the endpoint of a segment from the circle center that is perpendicular to the line. Hence each of the lines is a tangent at its reference point.

6 0

3 years ago