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SashulF [63]
2 years ago
12

If Avogadro's number of pennies is divided equally among the 246 million men, women, and children in the United States, how many

dollars would each receive
Mathematics
1 answer:
Vesna [10]2 years ago
4 0

USD per person = $2.31 × 10^{13}.

<h3>What is the US dollar?</h3>
  • The US dollar is the official currency of the United States and a number of other countries.
  • The Coinage Act of 1792 established the United States dollar on equal footing with the Spanish silver dollar, divided it into 100 cents, and authorized the minting of coins denominated in dollars and cents.

To find how many dollars would each receive:

Avogadro's number of pennies is divided equally among 261 million people.

Avogadro's number is 6.022 × 10^{23}.

To find the number of pennies each person will receive, we divide 6.022 × 10^{23} by 261 million.

Pennies per person = \frac{6.022  * 10^{23} }{261 million} = \frac{6.022 * 10^{23} }{261 * 10^{6} } = 2.31 * 10^{15}

This is equal to the number of cents each person receives.

To convert pennies into dollars, 1 USD = 100 pennies, divide 2.31 * 10^{15} by 100.

USD per person = \frac{2.31 * 10^{15} }{100} = $2.31 * 10^{13}

Therefore, USD per person = $2.31 × 10^{13}.

Know more about USD here:

brainly.com/question/24278371

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The question you are looking for is here:

If Avogadro's number of pennies is divided equally among the 261 million men, women, and children in the United States, how many dollars would each receive?

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Answer:

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What is the equation of a circle with center (−8, 3) and radius 8?
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Answer:

x^2 + y^2 + 16x + 6y + 9 = 0

Step-by-step explanation:

Using the formula for equation of a circle

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Inserting the values given in the question

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3 years ago
Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

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