Answer:
nitrate and sodium are spectator ions .The reactions that form an aqueous solution are often a spectator ions.
Given that there is 48 liters of gasoline to be burned and that 45 kJ of energy is released per gram of gasoline burned, the amount of energy that the gasoline fuel produces can then be calculated, First, we convert 48 liters of gasoline to units of mass (grams) in order to use the given conversion of 45 kJ per gram of gasoline. To do this, we use the density of gasoline which is 0.77 g/mL. The following expression is then used:
48 L gasoline x 1000 mL/L x 0.77 g/mL x 45 kJ/g gasoline = 1663200 kJ
<span>The amount of energy produced by burning 48 L of gasoline was then determined to be 1663200 kJ. </span>
Answer:
328 ml
Explanation:
We have given final volume =575.2 ml=0.575 L
Final concentration = 0.8012 M
We know that moles of copper(II) nitrate = final volume ×final concentration =0.8012×.0575=0.4606 moles
We have to find initial volume
So initial volume 
