The answer to your question is true.
Answer: 0.52 L of 15 M 
will be used to prepare this amount of 0.52 M base.
Explanation:
But on diluting the number of moles remain same and thus we can use molarity equation.
(to be prepared)
where,
=concentration of stock solution = 15 M
= volume of stock solution = ?
= concentration of solution to be prepared = 0.52 M
= volume of solution to be prepared = 15 L
Thus 0.52 L of 15 M will be used to prepare this amount of 0.52 M base
In science, physical quantities like length, weights etc are measured in units of metric or International System of units.
Some importance units are as follows:
1. Meter (m) for length.
2. Liter (L) for volume.
3. Gram (g) and kilogram (kg) for mass.
4. Degree Celsius (oC) for temperature.
5. Second for (s) time.
Given that the length of an object = 45.2 cm
SI unit of length is m
100 cm = 1.0 m
Therefore
45.2 cm * 1 .0 m/100 cm
= 0.452 m
A homogeneous mixture<span> is a </span>type of mixture<span> in which the composition is uniform and every part of the solution has the same properties. A heterogeneous </span>mixture<span> is a </span>type of mixture<span> in which the components can be seen, as there are two or more phases present.</span>
Answer:
1.51
⋅
10
24
Explanation:
This is a pretty straightforward example of how to sue Avogadro's number to figure out the number of molecules present in a given sample.
In your case, the sample is said to contain
2.50
moles of water. Now, a mole is simply a very, very large collection of molecules. In order to have
1
mole of a molecular compound you need your sample to contain
6.022
⋅
10
23
molecules of that compound.
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