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almond37 [142]
3 years ago
12

What is the voltage of a cell with half-reactions Zn(s) = Zn2+ + 2e-

Chemistry
1 answer:
chubhunter [2.5K]3 years ago
3 0

−−−−−−−−−−−−−−

Zn2+(aq)+2e⇌Zn(s)××××x−0.76

Cu2+(aq)+2e⇌Cu(s)××××x+0.34

×××××××××××−−−−−−−−−−−−−−−→

The 1/2 cell with the most +ve E∘ value will take in the electrons.

So we can see that the copper 1/2 cell will be driven left to right and the zinc 1/2 cell right to left as indicated by the arrows.

So the two 1/2 equations are:

Zn(aq)→Zn2+(aq)+2e

Cu2+(aq)+2e→Cu(s)

Adding these gives the cell reaction when it is working:

Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s)

When the zinc atoms lose electrons the zinc ions go into solution and the 2 electrons flow away from this electrode into the external circuit.

When they arrive at the copper electrode, they are picked up by the copper(II) ions to become copper atoms.

The two 1/2 cells are connected by a salt bridge or a membrane. The salt bridge consists of some filter paper soaked in a suitable electrolyte such as saturated potassium nitrate solution.

The function of the salt bridge is to maintain electrical neutrality in each half cell.

As zinc ions go into solution NO−3 ions flood in to the half cell.

As copper(II) ions leave the solution in the other 1/2 cell, K+ ions flood in.

To find the emf of the cell, subtract the least +ve E∘ value from the most +ve:

E∘cell=+0.34−(−0.76)=+1.1V

This arrangement is known as "The Daniel Cell".

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7 0
2 years ago
The solubility of glucose at 30°C is
weqwewe [10]

Answer:

Saturated solution

We should raise the temperature to increase the amount of glucose in the solution without adding more glucose.

Explanation:

Step 1: Calculate the mass of water

The density of water at 30°C is 0.996 g/mL. We use this data to calculate the mass corresponding to 400 mL.

400 mL \times \frac{0.996g}{1mL} =398g

Step 2: Calculate the mass of glucose per 100 g of water

550 g of glucose were added to 398 g of water. Let's calculate the mass of glucose per 100 g of water.

100gH_2O \times \frac{550gGlucose}{398gH_2O} = 138 gGlucose

Step 3: Classify the solution

The solubility represents the maximum amount of solute that can be dissolved per 100 g of water. Since the solubility of glucose is 125 g Glucose/100 g of water and we attempt to dissolve 138 g of Glucose/100 g of water, some of the Glucose will not be dissolved. The solution will have the maximum amount of solute possible so it would be saturated. We could increase the amount of glucose in the solution by raising the temperature to increase the solubility of glucose in water.

6 0
3 years ago
What is The mass of 1 gram
NARA [144]
One kilogram is the answer
3 0
2 years ago
Read 2 more answers
The single most important factor influencing potassium ion secretion is ________
Ne4ueva [31]

The single most important factor influencing potassium ion secretion is its concentration in blood plasma.

<h3>What is Plasma?</h3>

This is the liquid portion of the blood and serves as the transport medium for nutrients in the body.

When there is a high concentration in the plasma, it maximizes the concentration gradient which favors its secretion into the urinary fluid.

Read more about Plasma here brainly.com/question/2901507

4 0
2 years ago
What is the new boiling point if 25 g of NaCl is dissolved in 1.0 kg of water
Inessa05 [86]
The correct answer for the question that is being presented above is this one: 

Given that:
delta Tb = Kbm Kb H2O = 0.52 degrees C/m 
<span>delta Tf = Kfm Kf H2O = 1.86 degrees C/m 
</span>
We need to know the formula for Molality.
molality = mol solute / kg solvent 

<span>We are given the amount of solute in grams
Since amount of solute is given in moles, we have to convert 25 g NaCl to moles. Divide by molar mass. </span>

<span>25 g NaCl / 58.5 g/mol = 0.427 mol </span>

<span>Then, use the formula for molality. </span>

<span>molality = mol solute / kg solvent </span>
<span>= 0.427 / 1 </span>
<span>= 0.427 m </span>

<span>Use now the formula to get the boiling point.</span>

<span>delta Tb = Kbm </span>
<span>= (0.52)(0.427) </span>
<span>= 0.22C </span>
8 0
3 years ago
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