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2 years ago

✨42 POINTS✨PLEASE HELP 6th grade math!!! need answers for A B and C

Mathematics

1 answer:

Alex2 years ago

3 0

9514 1404 393

Answer:

A"(-6, 3)

B"(-9, 0)

C"(-5, -1)

Step-by-step explanation:

We presume the first transformation is a translation 4 units right and 1 unit up:

(x, y) ⇒ (x+4, y+1)

The second transformation negates the x-coordinate, so the two transformations together have the rule ...

(x, y) ⇒ (-(x+4), y+1)

Then the transformed points are ...

A"(-6, 3)

B"(-9, 0)

C"(-5, -1)

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3 years ago

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The length of the rectangle is 5/6 of inches and the width of the rectangle is 2/15 of inches. What is the area of the rectangle

Inga [223]

Answer:

W = X in.

L = (3x - 6) in.

A = L*W = (3x-6)X = 45,

3x^2 - 6x = 45

3x(x-2) = 45,

x(x-2) = 15,

x^2 - 2x - 15 = 0

(x-5)(x+3) = 0,

x-5 = 0,

x = 5 in.

x+3 = 0,

x = -3.

Solution Set: x = 5, and x = -3.

Select + value of X:

x = 5

W = x = 5 in.

L = 3x-6 = 3*5 - 6 = 9 in.

Step-by-step explanation:

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2 years ago

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ss7ja [257]

Answer:

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3 years ago

Enter the simplified form of the complex fraction in the box.

Ket [755]

The problem is:

$\frac{\frac{3}{x}+\frac{1}{4}}{1+\frac{3}{x}}$

We now do L.C.M. of numerator and add, also do L.C.M. of denominator and add together:

$\frac{\frac{12+x}{4x}}{\frac{x+3}{x}}$

Dividing by a fraction is same as multiplying by its reciprocal, so we have:

$\frac{12+x}{4x} * \frac{x}{x+3} \\$

x cancels out, so can multiply and write:

$\frac{12+x}{4} * \frac{1}{x+3} \\=\frac{12+x}{4x+12}$

This is the simplified form.

ANSWER: $\frac{12+x}{4x+12}$

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2 years ago

Is the ordered pair a solution of y ≥ 2x − 5? a. (3, 1) b. (1, −4)

Deffense [45]

Answer:

a. Yes

b. No

Step-by-step explanation:

To find if an ordered pair is a solution to the inequality, substitute its x and y values for the x and y in the inequality and solve. If the equation is true, then it is a solution. If it is not, then it is not a solution.

1) First, substitute the x and y values of (3, 1) into the inequality. So, substitute 3 for x and 1 for y:

$1 \geq 2(3)-5\\1\geq 6-5\\1\geq 1$

1 is greater than or equal to 1, so (3,1) is a solution.

2) Second, do the same with the point (1, -4). Substitute 1 for x and -4 for y:

$-4\geq 2(1)-5\\\\-4\geq 2-5\\-4\geq -3$

However, -4 is not greater than or equal to -3, thus (1, -4) is not a solution.

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3 years ago