Answer:
I = 5[amp]
Explanation:
Electrical power is defined as the product of voltage by current.

where:
P = power = 1150 [W]
V = voltage = 230 [V]
I = current [amp]
Now replacing:
![1150=230*I\\I=1150/230\\I=5[amp]](https://tex.z-dn.net/?f=1150%3D230%2AI%5C%5CI%3D1150%2F230%5C%5CI%3D5%5Bamp%5D)
A 15 [amp] fuse must be used. Always the fuse must be larger than the operating current, to protect the equipment from very high currents. above 15 [amp]
Answer:
a. I = 30 A
b. E = 1080000 J = 1080 KJ
c. ΔT = 12.86°C
d. Cost = $ 4.32
Explanation:
a.
The current in the coil is given by Ohm's Law:

where,
I = current = ?
V = Voltage = 120 V
R = Resistance = 4 Ω
Therefore,

<u>I = 30 A</u>
<u></u>
b.
The energy can be calculated as:

<u>E = 1080000 J = 1080 KJ</u>
<u></u>
c.
For the increase in the temperature of water:

where,
m = mass of water = 20 kg
C = specific heat of water = 4.2 KJ/kg.°C
Therefore,

<u>ΔT = 12.86°C</u>
<u></u>
d.
First, we will calculate the total energy consumed:

Now, for the cost:

<u>Cost = $ 4.32</u>
Answer:
The induced current will be counterclockwise.
Explanation:
Magnetic field lines always begin on north poles and end on south poles. This means that there is an increase of magnetic field lines going into the plane of the loop. The induced current will be counterclockwise to oppose this change.
F3 -4 wouldn’t even be a guhd add up tbsh jus delete it
Physical properties of water:
Color: No color/colorless.
Odor: Odorless.
Taste: Tasteless.
Density: 1 g/ml.
Boiling point: 100°C.
Freezing/Melting point: 0°C.
State or phase:
Vapor: Gas.
Room temperature: Liquid.
Ice: Solid.
Hence, water is a colorless, odorless, and tasteless substance whose density is 1 g/ml. It boils at 100°C and melts at 0°C. In the vapor phase, it is in a gaseous state, at room temperature, it exists in a liquid state, and when its freezes (ice) it's in the solid state.