Complete Question
The complete question(reference (chegg)) is shown on the first uploaded image
Answer:
The magnitude of the resultant force is 
The direction of the resultant force is
from the horizontal plane
Explanation:
Generally when resolving force, if the force (F )is moving toward the angle then the resolve force will be
while if the force is moving away from the angle then the resolved force is 
Now from the diagram let resolve the forces to their horizontal component
So


Now resolving these force into their vertical component can be mathematically evaluated as


Now the resultant force is mathematically evaluated as

substituting values


The direction of the resultant force is evaluated as
![\theta = tan^{-1}[\frac{F_y}{F_x} ]](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%20tan%5E%7B-1%7D%5B%5Cfrac%7BF_y%7D%7BF_x%7D%20%5D)
substituting values
![\theta = tan^{-1}[\frac{ 14.3}{199.128} ]](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%20tan%5E%7B-1%7D%5B%5Cfrac%7B%2014.3%7D%7B199.128%7D%20%5D)
from the horizontal plane
The location of the point F that partitions a line segment from D to E (
), that goes from <u>negative 4</u> to <u>positive 5,</u> into a 5:6 ratio is fifteen halves (option 4).
We need to calculate the segment of the line DE to find the location of point F.
Since point D is located at <u>negative -4</u> and point E is at <u>positive 5</u>, we have:

Hence, the segment of the line DE (
) is 9.
Knowing that point F partitions the line segment from D to E (
) into a <u>5:6 ratio</u>, its location would be:
Therefore, the location of point F is fifteen halves (option 4).
Learn more about segments here:
I hope it helps you!
The potential energy of the car when it let go is 20,000 J.
The speed of the car at the bottom of the ramp is 20 m/s.
The given parameters;
- <em>mass of the car, m = 100 kg</em>
- <em>height of the car, h = 20 m</em>
<em />
The potential energy of the car is calculated as follows;
P.E = mgh
P.E = 100 x 10 x 20
P.E = 20,000 J
The speed of the car at the bottom of the ramp is calculated as follows;

Learn more here:brainly.com/question/18597080
Answer:
The frequency of the infrared light is approximately 3.156 × 10¹⁴ Hz
Explanation:
Given that the wavelength of infrared light, λ = 9.50 × 10⁻⁷ m, we have;
The speed of light (which is constant), c = v × λ = 299,792,458 m
Where v = The frequency of the infrared light, we have;
v = c/λ = 299,792,458/(9.50 × 10⁻⁷) ≈ 3.156 × 10¹⁴ Hz
The frequency of the infrared light = v ≈ 3.156 × 10¹⁴ Hz.