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-Dominant- [34]
4 years ago
11

2. (a). Three forces that act on a particle are given by F1 = (20 i – 36 j + 73 k) N, F2 = (-17 i

Physics
1 answer:
AlladinOne [14]4 years ago
5 0
F3 -4 wouldn’t even be a guhd add up tbsh jus delete it
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A child bounces a 48 g superball on the sidewalk. The velocity change of the superball is from 28 m/s downward to 17 m/s upward.
Aliun [14]

Answer:

F = 1.2×10⁻³ N

Explanation:

From the question,

Applying newton's second law of motion,

F = m(v-u)/t................... Equation 1

Given: F = magnitude of the average force exerted on the ball, m = mass of the ball, v = final velocity, u = initial velocity, t = time of  contact.

Note: let downward be negative and upward be positive.

Given: m = 48 g = 48/1000 = 0.048 kg, v = 17 m/s, u = -28 m/s (downward),

t = 1800 s

Substitute into equation 1

F = 0.048(17-[28])/1800

F = 1.2×10⁻³ N

7 0
3 years ago
what is formed when two or more substances are so evenly mixed that you can't see the different parts
Andre45 [30]
A homogenous mixture
5 0
4 years ago
A 92kg astronaut and a 1200kg satellite are at rest relative to the space shuttle. The astronaut pushes on the satellite, giving
Harman [31]

Answer:

13.7m

Explanation:

Since there's no external force acting on the astronaut or the satellite, the momentum must be conserved before and after the push. Since both are at rest before, momentum is 0.

After the push

m_av_a + m_sv_s = 0

Where m_a = 92kg is the mass of the astronaut, m_s = 1200kg is the mass of the satellite, v_s = 0.14 m/s is the speed of the satellite. We can calculate the speed v_a of the astronaut:

v_a = \frac{-m_sv_s}{m_a} = \frac{-1200*0.14}{92} = -1.83 m/s

So the astronaut has a opposite direction with the satellite motion, which is further away from the shuttle. Since it takes 7.5 s for the astronaut to make contact with the shuttle, the distance would be

d = vt = 1.83 * 7.5 = 13.7 m

4 0
3 years ago
If there are 1.609 km in a mile, convert 135 miles/hour into meters per second. There are 1000 m in a kilometer.
Effectus [21]

Answer:

97.1037936

Explanation:

?

4 0
3 years ago
Read 2 more answers
A radio wave has a frequency of 4.40 × 108 hz. what is the energy (in j) of one photon of this radiation? enter your answer in s
LiRa [457]
The energy of a single photon is given by
E=hf
where 
h=6.6 \cdot 10^{-34} Js is the Planck constant
f is the frequency of the wave (of the photon)

In our problem, the radio wave has a frequency of f=4.40 \cdot 10^8 Hz, so if we put this value into the previous formula, we can find the energy of a single photon of this electromagnetic wave:
E=hf=(6.6 \cdot 10^{-34} Js)(4.40 \cdot 10^8 Hz)=2.9 \cdot 10^{-25} J
7 0
3 years ago
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