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mihalych1998 [28]
3 years ago
5

If one were to stack thick fabric fabric on top of one another, then push the opposite ends towards one another, resulting and b

ending and rumpling, this would illustrate what physical process?
Physics
1 answer:
lawyer [7]3 years ago
3 0

Answer:

The answer is "folding".

Explanation:

It is a physical reconfiguring of the process, which gives a fabric a softer, lightweight shape. It is achieved in a far less simple space to carry or store products.  

  • When one places effect sizes on each other, instead move the different ends to each other and fold and roll it, its linear function of Folding would be illustrated.  
  • Except in geography, the piling process naturally creates space to makes the surface clearer and lighter.
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What layer of the atmosphere is hot but does not have enough gas molecules to transfer heat to you (i.e., you would not feel the
fenix001 [56]

Answer:

thermosphere...........

7 0
3 years ago
A ball of mass m is thrown into the air in a 45° direction of the horizon, after 3 seconds the ball is seen in a direction 30° f
Rzqust [24]

Answer:

Velocity (magnitude) is 98.37 m/s

Explanation:

We use the vertical component of the initial velocity, which is:

v_{0y}=v_0*sin(45)=\frac{\sqrt{2} }{2}v_0

Using kinematics expression of vertical velocity (in y direction) for an accelerated motion (constant acceleration, which is gravity):

v_{y}=v_{0y}+a*t=\frac{\sqrt{2} }{2}v_0-9.8t

Now we need to find v_y as a function of v_0. We use the horizontal velocity, which is always the same as follow:

v_x=v_0cos(45\º)=\frac{\sqrt{2} }{2}v_0=v_{t=3}*cos(30\º) \\

We know the angle at 3 seconds:

v_y(t=3)=v_{t=3}*sin(30\º)\\v_{t=3}=\frac{v_y}{sin(30\º)}

Substitute  v_{t=3} in  v_x and then solve for  v_y

\frac{\sqrt{2} }{2}v_0=\frac{v_y*cos(30\º) }{sin(30\º)} \\v_y=\frac{\sqrt{6} }{6}v_0

With this expression we go back to the kinematic equation and solve it for initial speed

\frac{\sqrt{6} }{6} v_0 =\frac{\sqrt{2} }{2}v_0-29.4\\v_0(\frac{\sqrt{6}-3\sqrt{2}}{6} )=-29.4\\v_0=98.37 m/s

3 0
4 years ago
Two fish swimming in a river have the following equations of motion:
IRINA_888 [86]

Answer:

The second fish, X2, is moving faster than the first fish, X1

Explanation:

The given parameters for the equation of motion of the fishes are;

X1 = -6.4 m + (-1.2 m/s)×t

X2 = 1.3 m + (-2.7 m/s)×t

The given equation are straight line equations in the slope and intercept form, where the slope is the speed and in m/s and the intercept is the starting point of swimming of the fishes

For the first fish, the intercept = -6.4 m, the slope = the  speed = -1.2 m/s

For the second fish, the intercept = 1.3 m, the slope = the  speed = -2.7 m/s

Whereby the fishes are swimming in the opposite direction of the measurement of length, we have;

The magnitude of the speed of the second fish \left | -2.7 \ m/s \right | = 2.7 \ m/s, is larger than the magnitude of the speed of the first fish \left | -1.2 \ m/s \right | = 1.2 \ m/s

Therefore, the second fish, X2, is moving faster than the first fish, X1.

8 0
3 years ago
Relate the output of energy from a heat engine to the energy put into the heat engine considering the second law of thermodynami
Vinil7 [7]

<u>Answer: </u>

<em>Considering the II law of thermodynamics</em>

<em>From the figure</em>

<em>Out put of energy: </em>

Heat supplied from the source/ reservoir  (Q₁) - Heat rejected to the surroundings from the system (Q) = Q₁ - Q₂. Also known as Net work done on the system.

<em>Input of energy: </em>

Amount of heat energy supplied to the system from the source (Q₁ ).

Efficiency (H.E) = η = Output÷ Input

                             η  = (Q₁ - Q₂) ÷ Q₁

                      OR η = Wnet ÷ Q₁ ;        since Wnet = (Q₁ - Q₂)


3 0
3 years ago
1. Write the following degrees in radian measure
svp [43]
C is the right answer

I hooe this helps
6 0
3 years ago
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