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Tcecarenko [31]
3 years ago
14

Which method do you prefer, using a giant one or a percent ruler? Why?-

Mathematics
1 answer:
emmasim [6.3K]3 years ago
3 0
A percent beacause it can be more beneficial and alot more exact

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A glass is 1/3 full.
Setler79 [48]

Answer:

216 cm³

Step-by-step explanation:

1/3x + 63 = 5/8x

subtract 1/3x from each side; (1/3x = 8/24x  and  5/8x = 15/24x)

63 = 7/24x

7x = 63(24)

7x = 1512

x = 216

4 0
3 years ago
Conor has $200 available to buy software
fiasKO [112]
Don’t go to that link it is a virus it’s a bot doing that do not go to that link
8 0
3 years ago
Rectangles J and K are similar. If the area of rectangle J is 440, what is the area of rectangle K? I need this today
Hunter-Best [27]

Answer:

Area = 27.5

Step-by-step explanation:

Given

J_{Area} = 440

J_{Width} = 22

K_{Width} = 5.5

<em>See attachment</em>

Required

Determine the area of K

First, we need to calculate the length of the rectangle  J

J_{Length} * J_{Width} = J_{Area}

This gives:

J_{Length} * 22 = 440

Divide both sides by 22

\frac{J_{Length} * 22}{22} = \frac{440}{22}

J_{Length} = 20

So, the length of the rectangle J is 20.

Since both shapes are similar, then:

J_{Length} : J_{Width} = K_{Length} : `K_{Width}

Substitute the known values:

20 : 22 = K_{Length} : `5.5

Express as fraction:

\frac{20 }{ 22 }= \frac{K_{Length} }{ `5.5}

Make Length, the subject of formula

K_{Length} = \frac{5.5 * 20}{22}

K_{Length} = \frac{110}{22}

K_{Length} = 5

The area of K is:

Area = K_{Length} * K_{Width

Area = 5.5 * 5

Area = 27.5

4 0
3 years ago
A ship leaves port at noon and has a bearing of S29oW. The ship sails at 20 knots. How many nautical miles south and how many na
ira [324]

Answer:

Approximately 58.2\; \text{nautical miles} (assuming that the bearing is {\rm S$29^{\circ}$W}.)

Step-by-step explanation:

Let v denote the speed of the ship, and let t denote the duration of the trip. The magnitude of the displacement of this ship would be v\, t.

Refer to the diagram attached. The direction {\rm S$29^{\circ}$W} means 29^{\circ} west of south. Thus, start with the south direction and turn towards west (clockwise) by 29^{\circ} to find the direction of the displacement of the ship.

The hypothenuse of the right triangle in this diagram represents the displacement of the ship, with a length of v\, t. The dashed horizontal line segment represents the distance that the ship has travelled to the west (which this question is asking for.) The angle opposite to that line segment is exactly 29^{\circ}.

Since the hypotenuse is of length v\, t, the dashed line segment opposite to the \theta = 29^{\circ} vertex would have a length of:

\begin{aligned}& \text{opposite (to $\theta$)} \\ =\; & \text{hypotenuse} \times \frac{\text{opposite (to $\theta$)}}{\text{hypotenuse}} \\ =\; & \text{hypotenuse} \times \sin (\theta) \\ =\; & v\, t \, \sin(\theta) \\ =\; & v\, t\, \sin(29^{\circ})\end{aligned}.

Substitute in \begin{aligned} v &= 20\; \frac{\text{nautical mile}}{\text{hour}}\end{aligned} and t = 6\; \text{hour}:

\begin{aligned} & v\, t\, \sin(29^{\circ}) \\ =\; & 20\; \frac{\text{nautical mile}}{\text{hour}} \times 6\; \text{hour} \times \sin(29^{\circ}) \\ \approx\; & 58.2\; \text{nautical mile}\end{aligned}.

7 0
3 years ago
What is 15/y+11 - 10/y+3 = 0
Scrat [10]
15/y+11-10/y+3=0
15/y-10/y=5/y  11+3=14
5/y+14=0
o-14=-14
5/y=-14
y=-5/14
3 0
3 years ago
Read 2 more answers
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