To divide 53 by 8 wont be possible so u find a number that when you multiply by 8 it gives u a number closer to 58 which is 8*6=48 i.e 53 divided by 8 is 6 rem, then to get the reminder you subtract 42 from 53 i.e 53–48=5 so the final answer will be 6 and 5/6
What is the approximate volume of the cylinder? Use 3.14 for π. 9 Hight and 4 length.
1 answer:
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To divide 53 by 8 wont be possible so u find a number that when you multiply by 8 it gives u a number closer to 58 which is 8*6=48 i.e 53 divided by 8 is 6 rem, then to get the reminder you subtract 42 from 53 i.e 53–48=5 so the final answer will be 6 and 5/6
Answer:
A)Mean :10.65
Median =10.7
Mode : 10.7
B)Range = 3.5
Standard deviation :0.89916
C)The response time of 8.3 minutes should be considered an outlier in comparison to the other response times
Step-by-step explanation:
A)
Data : 11.8 ,10.3, 10.7, 10.6, 11.5, 8.3, 10.5, 10.9, 10.7, 11.2
Mean = 10.65
Median: The mid value of the data
Data in ascending order
8.3
10.3
10.5
10.6
10.7
10.7
10.9
11.2
11.5
11.8
n=10(even)
Mode : the most occurring frequency
10.7 is occurring twice while others are occurring once
So, Mode is 10.7
B) Range = Maximum - Minimum=11.8-8.3=3.5
Standard deviation :
Standard deviation :
Standard deviation :0.89916
C)
8.3
,10.3
,10.5
,10.6
,10.7
,10.7
,10.9
,11.2
,11.5
,11.8
For Q1 ( Median of lower quartile )
8.3
,10.3
,10.5
,10.6
,10.7
For Q3( Median of Upper quartile )
10.7
,10.9
,11.2
,11.5
,11.8
IQR = Q3-Q1=11.2-10.5=0.7
Range :(Q1-1.5IQR, Q3-1.5IQR)
Range :
Range :(9.45, 10.15)
8.3 does not lie in this interval
So, the response time of 8.3 minutes should be considered an outlier in comparison to the other response times