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s2008m [1.1K]
3 years ago
13

What is an advantage that experimental probability has over theoretical probability?

Mathematics
2 answers:
DIA [1.3K]3 years ago
8 0

C. It is not always possible to calculate theoretical probability in complex situations, but experimental probability can be calculated any time experiments can be run.


alekssr [168]3 years ago
4 0

Answer:

the answer is c It is not always possible to calculate theoretical probability in complex situations, but experimental probability can be calculated any time experiments can be run.

I hope this helps and i it does please rate 5 stars and a brainliest :) thankyou!



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Need help with questions <br> 2. and 3.
emmainna [20.7K]

9514 1404 393

Answer:

  2)  x = 7

  3)  x = 5

Step-by-step explanation:

When a transversal crosses parallel lines, all of the acute angles are congruent, and all of the obtuse angles are congruent. When it crosses at right angle, all of the angles are right angles.

2) All of the angles are right angles.

  11x +13 = 90

  11x = 77 . . . . . . subtract 13

  x = 7 . . . . . . . divide by 11

__

3) The two marked angles are acute.

  16x = 80 . . . . the acute angles are congruent

  x = 5 . . . . . . divide by 16

5 0
2 years ago
What is equivalent to<br>x2+ 14x = -13​
postnew [5]

Answer:

X= 1 AND 13

Step-by-step explanation:

x2+14x = -13

by completing the square method

you add the square of half the coefficient of b to both sides

which is (14/2)^2

x^2+14x+(7^2) = -13 +(7^2)

x^2 + 7^2 = -13 + 49

x^2 + 7^2 = 36

(x + 7)^2 = 36

find the square root of both sides

(x+7) = + or - 6

x=7-6 ; 1

or

x= 7+6 ; 13

8 0
2 years ago
The question is below could you explain in detail thank you so much!!!
Ivan
I think is 1863 m because if you use the formula for area 
8 0
3 years ago
Read 2 more answers
What is the solution set of the inequality x5 + x4 - 6x3 + x2 + x - 6 ≥ 0?
Ainat [17]
The answer is C

because:
6 0
3 years ago
Help!!!!!!!!!!!!!!!!!!!!!!!
Nataly [62]
Hello.

Firstly, let's isolate x on the equation:

\mathsf{f(x) = 3x + 3} \\ \\ \mathsf{y = 3x + 3} \\ \\ \mathsf{-3x = -y + 3} \\ \\ \mathsf{x = \dfrac{-y + 3}{3}}

Now, we can replace 'x' for 'y' and vice-versa:

\mathsf{f^{-1}(x) = \frac{-x + 3}{3}`}

Hope I helped.
4 0
3 years ago
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