Step 1: <span>Set up the long division.
_______
4| 3 2 2 0
Step 2: </span><span>Calculate 32 ÷ 4, which is 8.
</span> __ 8____
4| 3 2 2 0
3 2
Step 3: Bring down 20, so that 20 is large enough to be divided by 4.
__ 8____
4| 3 2 2 0
3 2
_________
2 0
Step 4: Calculate<span> 20 ÷ 4, which is 5.
8 0 5
</span> ________
4| 3 2 2 0
3 2
________
2 0
2 0
____
Step 5: Therefore,<span> 3,220 ÷ 4 = 805.
The answer is 805
Done! :)</span>
At 1/8 of a gallon you can mow 2 1/4 so for 1 gallon just multiply 2 1/4 by 8
16+2 is 18
Answer:
An explicit representation for the nth term of the sequence:
It means, option (B) should be true.
Step-by-step explanation:
Given the geometric sequence
A geometric sequence has a constant ratio, denoted by 'r', and is defined by
Determining the common ratios of all the adjacent terms
As the ratio is the same, so
r = 4
Given that f₁ = -1/2
substituting r = 4, and f₁ = -1/2 in the nth term
Thus, an explicit representation for the nth term of the sequence:
It means, option (B) should be true.
4n+7−(7n−8)
=4n+7+−1(7n−8)
=4n+7+−1(7n)+(−1)(−8)
=4n+7+−7n+8
Combine Like Terms
=4n+7+−7n+8
=(4n+−7n)+(7+8)
=−3n+15
Answer:
a) 0.70
b) 0.82
Step-by-step explanation:
a)
Let M be the event that student get merit scholarship and A be the event that student get athletic scholarship.
P(M)=0.3
P(A)=0.6
P(M∩A)=0.08
P(not getting merit scholarships)=P(M')=?
P(not getting merit scholarships)=1-P(M)
P(not getting merit scholarships)=1-0.3
P(not getting merit scholarships)=0.7
The probability that student not get the merit scholarship is 70%.
b)
P(getting at least one of two scholarships)=P(M or A)=P(M∪A)
P(getting at least one of two scholarships)=P(M)+P(A)-P(M∩A)
P(getting at least one of two scholarships)=0.3+0.6-0.08
P(getting at least one of two scholarships)=0.9-0.08
P(getting at least one of two scholarships)=0.82
The probability that student gets at least one of two scholarships is 82%.
