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aksik [14]
3 years ago
11

10. Which of the following group of colors of the visible light is listed from

Chemistry
1 answer:
scZoUnD [109]3 years ago
3 0

Answer:

The correct answer is - D. Red, green, violet​.

Explanation:

Visible light is the spectrum of light that can be seen by the naked eyes of humans without any equipment. This spectrum has various frequency light that helps us see things in color. The frequency of light ranges between seven different colors in which violet has the highest frequency and red has the lowest.

The different frequencies are as follows:

color               frequency

red (limit) 1.77

red                  1.91

orange  2.06

yellow  2.14

green  2.25

cyan  2.48

blue          2.75

violet (limit) 3.10

On this basis of this the group of colors of the visible light is listed from

lowest to the highest frequency - Red, green, violet​

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Explanation:

Please find the Measures of Center and construct a histogram AND find the 5-number summary and construct a box-n-whisker plot for the numbers below.

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A volume of 129 mL of hydrogen is collected over water. The water level in the collecting vessel is the same as the outside leve
mixas84 [53]

Explanation:

As it is given that water level is same as outside which means that theoretically, P = 756.0 torr.

So, using ideal gas equation we will calculate the number of moles as follows.

                  PV = nRT

or,           n = \frac{PV}{RT}

                 = \frac{\frac{756}{760}atm \times 0.129 L}{0.0821 Latm/mol K \times 298 K}

                  = 0.0052 mol

Also,  No. of moles = \frac{mass}{\text{molar mass}}

               0.0052 mol = \frac{mass}{2 g/mol}

                  mass = 0.0104 g

As some of the water over which the hydrogen gas has been collected is present in the form of water vapor. Therefore, at 25^{o}C

                P_{\text{water vapor}} = 24 mm Hg

                                = \frac{24}{760} atm

                                = 0.03158 atm

Now,   P = \frac{756}{760} - 0.03158

              = 0.963 atm

Hence,   n = \frac{0.963 atm \times 0.129 L}{0.0821 L atm/mol K \times 298 K}

                 = 0.0056 mol

So, mass of H_{2} = 0.0056 mol × 2

                         = 0.01013 g (actual yield)

Therefore, calculate the percentage yield as follows.

      Percent yield = \frac{\text{Actual yield}}{\text{Theoretical yield}} \times 100

                              = \frac{0.01013 g}{0.0104 g} \times 100            

                              = 97.49%

Thus, we can conclude that the percent yield of hydrogen for the given reaction is 97.49%.

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the answer to the qustion is 0.013089701 na

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n/a

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