Question

Find an equation of the line that contains the following pair of points. (3,2) and (1,3) The equation of the line is (Simnlif vour ancwor Llco.intogore or fractione.for anu.numborc.in.the aquatio

Answer 1

Answer: $x+2y-7=0$

Step-by-step explanation:

We know that the equation of a line passing through points (a,b) and (c,d) is given by :-

$(y-b)=\dfrac{d-b}{c-a}(x-a)$

Then , the equation of a line passing through points (3,2) and (1,3) is given by :-

$(y-2)=\dfrac{3-2}{1-3}(x-3)\\\\\Rightarrow\ (y-2)=\dfrac{1}{-2}(x-3)\\\\\Rightarrow\ -2(y-2)=(x-3)\\\\\Rightarrow\ -2y+4=x-3\\\\\Rightarrow\ x+2y-7=0$

Hence, the equation of a line passing through points (3,2) and (1,3) is : $x+2y-7=0$